The real numbers are not enough to solve , and the complex numbers come from adding a solution of that one equation. The surprise is that this one addition is enough for every polynomial equation of degree at least . No matter how high the degree, and even when the coefficients are themselves complex, such an equation has a solution among the complex numbers, so nothing larger is ever needed.
Key terms
Nonconstant complex polynomials
Definition A complex polynomial is an expression
where is a nonnegative integer and the coefficients are complex numbers. If , the degree is and is the leading coefficient. The polynomial is nonconstant when its degree is at least . A zero of is a complex number with . Real numbers are complex numbers, so every polynomial with real coefficients is also a complex polynomial.
In plain words The same kind of polynomial as before, except that the coefficients and the variable may be complex. Nonconstant means that the variable really appears.
Example The polynomial has degree , leading coefficient and constant term . The constant polynomial has degree and no zeros at all, which is why the theorem below asks for a nonconstant polynomial.
Existence of a complex zero
Definition The Fundamental Theorem of Algebra states that every nonconstant polynomial with complex coefficients has at least one zero in . The theorem is about existence. It does not give a formula for the zero, and for general polynomials of degree and higher no formula built from the coefficients with arithmetic and roots exists. Its proofs use ideas from beyond algebra, such as continuity.
In plain words Any polynomial equation with nonconstant has a complex solution. Over the real numbers this fails, since has no real zero.
Example The polynomial has complex coefficients, and the theorem promises a zero. One is
The other zero is .
Complex factorization
Definition Every polynomial of degree with complex coefficients can be written as
where is the leading coefficient and are complex numbers, not necessarily different. The list is unique apart from its order, and it consists exactly of the zeros of . The proof repeats one step. The theorem gives a zero , the Factor Theorem gives with of degree , and the same argument applies to until a constant is left.
In plain words Over the complex numbers, every polynomial breaks all the way down into linear factors, one for each unit of degree.
Example Over the reals, the polynomial splits into , and the last factor has no real zeros. Over it splits completely,
Counting zeros with multiplicity
Definition Let be a nonzero polynomial and a complex number. The multiplicity of is the largest integer such that divides . The number is a zero exactly when . For a zero this is the multiplicity from the lesson on zeros and multiplicity, the exponent with and . In the complex factorization, the multiplicity of is the number of factors equal to . It follows that a polynomial of degree has exactly complex zeros when each zero is counted as many times as its multiplicity, and therefore at most different zeros.
In plain words The degree tells you how many zeros there are, as long as you count over the complex numbers and count a repeated zero once for each time its factor appears.
Example The polynomial
has degree . Since , its zeros are
| Zero | Multiplicity |
|---|---|
The multiplicities add up to , the degree, while there are only three different zeros and just one of them is real.
Real coefficients and conjugate pairs
Definition Let have real coefficients. If a complex number is a zero of , then its conjugate is also a zero, with the same multiplicity. The reason for the first part is that conjugation respects sums and products and leaves real coefficients unchanged, so
So the nonreal zeros of a real polynomial come in conjugate pairs. As a consequence, a polynomial with real coefficients and odd degree has at least one real zero. The rule needs real coefficients. The polynomial has the zero but not .
In plain words For a polynomial with real coefficients, the nonreal zeros are mirror images of each other across the real axis. Knowing one of them gives you its partner for free.
Example The number is a zero of , which has real coefficients. So is a zero too. The sum of the coefficients is , so is a zero as well. A cubic has exactly three zeros counted with multiplicity, so the zeros are , and . As a check, the pair gives the factor , and multiplying out confirms
Real irreducible quadratic factors
Definition A quadratic with real coefficients and is irreducible over the reals when it is not a product of two linear factors with real coefficients. This happens exactly when it has no real zeros, that is when . For a complex number , multiplying the linear factors of the pair and always gives a quadratic with real coefficients,
and it is irreducible when is not real. Grouping each conjugate pair this way shows that every polynomial with real coefficients and degree at least is its leading coefficient times a product of real linear factors and real irreducible quadratic factors with .
In plain words If you want to stay with real numbers, you cannot always split a polynomial into linear pieces. You can always split it into linear pieces and quadratics with no real zeros, and that is as far as real factoring goes.
Example The polynomial has no real zeros, yet it does factor over the reals. Its complex zeros are and . For instance , so . The real coefficients make the conjugate a zero too, and since only even powers of appear, the negatives and are zeros as well. A polynomial of degree has at most four different zeros, so these are all of them. Pairing conjugates gives
Their product is the real factorization
Both quadratics have discriminant , so neither splits further over the reals. This kind of real factorization is the starting point for integrating rational functions by partial fractions.
Check yourself
- List the zeros of with their multiplicities, and check that the count matches the degree.
Show the answer
Since , the zero has multiplicity and the zeros and each have multiplicity . The total is , the degree of .
- The number is a zero of . Find all zeros and factor over the reals.
Show the answer
The coefficients are real, so is also a zero. These two give the real factor
Dividing gives , so the zeros are , and . The quadratic is irreducible over the reals, since its discriminant is .
- Find a polynomial with real coefficients, leading coefficient and the least possible degree that has the zeros and .
Show the answer
Real coefficients force to be a zero as well, so the degree is at least . The pair gives , and