Unit 2, lesson 22

End Behavior of Polynomials

How the degree and the sign of the leading coefficient decide what a polynomial does far to the left and far to the right, and why the leading term takes over for large inputs.

  • Theory part 43
  • Practice part 44
  • Polynomial Functions

Zoom out far enough on the graph of a polynomial and the bumps near the origin shrink into a small blur. What is left are two tails, one on the left and one on the right, each heading up or down. A single term of the formula decides both tails, so you can predict them before plotting anything.

Key terms

Polynomial and leading term

Definition A polynomial function is a function of the form

p(x)=anxn+an−1xn−1+⋯+a1x+a0,\begin{aligned} p(x) &= a_n x^n + a_{n - 1} x^{n - 1} \\[0.4em] &\quad + \dots + a_1 x + a_0, \end{aligned}

where nn is a nonnegative integer and the coefficients a0,a1,…,ana_0, a_1, \dots, a_n are real numbers. Its domain is all real numbers. When an≠0a_n \ne 0, the term anxna_n x^n is the leading term, ana_n is the leading coefficient and a0a_0 is the constant term. Read these only after combining like terms and writing the powers in decreasing order, which is called standard form. The zero polynomial, with every coefficient 00, has no leading term.

In plain words A polynomial adds up constant multiples of whole number powers of xx. The leading term is the one with the highest power that is actually present.

Example The polynomial p(x)=7+2x−5x3+x2p(x) = 7 + 2x - 5x^3 + x^2 has the standard form p(x)=−5x3+x2+2x+7p(x) = -5x^3 + x^2 + 2x + 7. Its leading term is −5x3-5x^3, its leading coefficient is −5-5 and its constant term is 77.

Degree

Definition The degree of a nonzero polynomial is the exponent nn of its leading term, the highest power of xx with a nonzero coefficient. A nonzero constant has degree 00, and the zero polynomial is not assigned a degree. For nonzero polynomials pp and qq, the degree of the product pqpq is the sum of their degrees, and the leading coefficient of pqpq is the product of their leading coefficients.

In plain words The degree is the biggest exponent. For a product of factors you can find it without multiplying out, by adding the degrees of the factors.

Example In p(x)=(2x−1)3(x+4)2p(x) = (2x - 1)^3 (x + 4)^2 the leading terms of the factors are (2x)3=8x3(2x)^3 = 8x^3 and x2x^2. So pp has degree 3+2=53 + 2 = 5 and leading term 8x58x^5, found without expanding anything.

End behavior

Definition The end behavior of a function ff describes what f(x)f(x) does as x→∞x \to \infty, meaning as xx increases without bound, and as x→−∞x \to -\infty, meaning as xx decreases without bound. The statement

f(x)→∞asx→∞f(x) \to \infty \quad \text{as} \quad x \to \infty

means that for every number KK there is a number MM with f(x)>Kf(x) > K whenever x>Mx > M. The statement f(x)→−∞f(x) \to -\infty as x→∞x \to \infty means that for every KK there is an MM with f(x)<Kf(x) < K whenever x>Mx > M. The versions for x→−∞x \to -\infty use x<Mx < M in place of x>Mx > M.

In plain words End behavior is about the far left and the far right of the graph. Saying that f(x)f(x) goes to infinity does not name a value. It says the outputs eventually pass every bound you pick and stay past it.

Example For f(x)=−x3f(x) = -x^3 the inputs x=10,100,1000x = 10, 100, 1000 give −103,−106,−109-10^3, -10^6, -10^9, and the inputs x=−10,−100,−1000x = -10, -100, -1000 give 103,106,10910^3, 10^6, 10^9. So f(x)→−∞f(x) \to -\infty as x→∞x \to \infty and f(x)→∞f(x) \to \infty as x→−∞x \to -\infty. The graph rises on the left and falls on the right.

Even and odd degree

Definition Let nn be a positive integer and look at the power function y=xny = x^n.

  1. If nn is even, then (−x)n=xn≥0(-x)^n = x^n \ge 0 for every xx, and xn→∞x^n \to \infty both as x→∞x \to \infty and as x→−∞x \to -\infty.
  2. If nn is odd, then (−x)n=−xn(-x)^n = -x^n, and xn→∞x^n \to \infty as x→∞x \to \infty while xn→−∞x^n \to -\infty as x→−∞x \to -\infty.

A polynomial has even degree or odd degree when its degree nn is even or odd. For degree n≥1n \ge 1, the leading coefficient test below shows that its tails follow the same pattern as xnx^n, turned upside down when the leading coefficient is negative.

In plain words Even powers send both ends of the graph the same way, up, like y=x2y = x^2. Odd powers send the two ends opposite ways, down on the left and up on the right, like y=x3y = x^3.

Example Here are the first few powers at x=−10x = -10 and x=10x = 10.

xxx2x^2x3x^3x4x^4x5x^5
−10-10100100−1000-100010,00010{,}000−100,000-100{,}000
10101001001000100010,00010{,}000100,000100{,}000

The even powers give the same value at both inputs, and the odd powers give opposite values.

Leading coefficient test

Definition Let pp be a polynomial of degree n≥1n \ge 1 with leading coefficient ana_n. Then pp has the same end behavior as its leading term anxna_n x^n.

Degree nnLeading coefficientAs x→−∞x \to -\inftyAs x→∞x \to \infty
evenan>0a_n > 0p(x)→∞p(x) \to \inftyp(x)→∞p(x) \to \infty
evenan<0a_n < 0p(x)→−∞p(x) \to -\inftyp(x)→−∞p(x) \to -\infty
oddan>0a_n > 0p(x)→−∞p(x) \to -\inftyp(x)→∞p(x) \to \infty
oddan<0a_n < 0p(x)→∞p(x) \to \inftyp(x)→−∞p(x) \to -\infty

The test says nothing about the middle of the graph, such as where the zeros or the turning points are.

In plain words Two facts settle both tails. Even or odd degree tells you whether the tails point the same way or opposite ways, and the sign of the leading coefficient tells you which way the right tail points.

Example For p(x)=−2x4+5x3+x−7p(x) = -2x^4 + 5x^3 + x - 7 the degree 44 is even and the leading coefficient −2-2 is negative, so the graph falls on both ends. Two spot values agree with this, p(10)=−14,997p(10) = -14{,}997 and p(−10)=−25,017p(-10) = -25{,}017.

Limits at infinity

Definition Informally, lim⁡x→∞f(x)=L\lim_{x \to \infty} f(x) = L means that f(x)f(x) gets and stays as close to the number LL as you like once xx is large enough, and lim⁡x→∞f(x)=∞\lim_{x \to \infty} f(x) = \infty is another way to write f(x)→∞f(x) \to \infty as x→∞x \to \infty. The same notation is used as x→−∞x \to -\infty. For a polynomial of degree n≥1n \ge 1 and every x≠0x \ne 0,

p(x)=anxn(1+an−1anx+⋯+a0anxn).\begin{aligned} p(x) &= a_n x^n \biggl(1 + \frac{a_{n - 1}}{a_n x} \\[0.8em] &\qquad + \dots + \frac{a_0}{a_n x^n}\biggr). \end{aligned}

Each fraction inside the bracket tends to 00 as x→∞x \to \infty and as x→−∞x \to -\infty, so the bracket tends to 11 and

lim⁡x→±∞p(x)anxn=1.\lim_{x \to \pm\infty} \frac{p(x)}{a_n x^n} = 1.

In particular, once ∣x∣\lvert x \rvert is large enough the bracket lies between 12\frac{1}{2} and 32\frac{3}{2}. Then p(x)p(x) has the same sign as anxna_n x^n and ∣p(x)∣≥12∣an∣∣x∣n\lvert p(x) \rvert \ge \frac{1}{2} \lvert a_n \rvert \lvert x \rvert^n, which is why the leading coefficient test holds. The precise definition of a finite limit at infinity comes in the lesson on horizontal asymptotes and again in the calculus lesson on limits at infinity.

In plain words Far from the origin the highest power is so much bigger than the others that their share of the total keeps shrinking. Zoomed out, the graph of a polynomial looks like the graph of its leading term.

Example Compare p(x)=x3−12x2p(x) = x^3 - 12x^2 with its leading term x3x^3.

xxp(x)p(x)p(x)x3\frac{p(x)}{x^3}
1010−200-200−0.2-0.2
100100880,000880{,}0000.880.88
10001000988,000,000988{,}000{,}0000.9880.988

At x=10x = 10 the polynomial is still negative, so the leading term has not taken over yet. The table is only evidence. The algebra is what proves the pattern, since

p(x)x3=1−12x,x≠0,\frac{p(x)}{x^3} = 1 - \frac{12}{x}, \qquad x \ne 0,

which tends to 11. Also p(x)=x2(x−12)p(x) = x^2(x - 12) is positive for every x>12x > 12.

Check yourself

  1. Describe the end behavior of p(x)=−3x5+40x4+2p(x) = -3x^5 + 40x^4 + 2.
Show the answer

The degree 55 is odd and the leading coefficient −3-3 is negative. So p(x)→∞p(x) \to \infty as x→−∞x \to -\infty and p(x)→−∞p(x) \to -\infty as x→∞x \to \infty. The graph rises on the left and falls on the right, even though p(10)=100,002p(10) = 100{,}002 is still positive.

  1. Find the degree, the leading coefficient and the end behavior of p(x)=(1−2x)3(x+1)2p(x) = (1 - 2x)^3 (x + 1)^2.
Show the answer

The leading terms of the factors are (−2x)3=−8x3(-2x)^3 = -8x^3 and x2x^2, so the leading term of pp is −8x5-8x^5. The degree is 55 and the leading coefficient is −8-8. Odd degree with a negative leading coefficient means the graph rises on the left and falls on the right.

  1. For p(x)=x4−100x3p(x) = x^4 - 100x^3, compute p(50)p(50). Does the result contradict the end behavior of pp?
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The value is p(50)=6,250,000−12,500,000=−6,250,000p(50) = 6{,}250{,}000 - 12{,}500{,}000 = -6{,}250{,}000. There is no contradiction. The degree is even and the leading coefficient is positive, so p(x)→∞p(x) \to \infty as x→∞x \to \infty, but that only describes large inputs. Since p(x)=x3(x−100)p(x) = x^3(x - 100), the values are positive for every x>100x > 100, for example p(200)=800,000,000p(200) = 800{,}000{,}000.

How this lesson connects

Where this leads in Calculus