Unit 2, lesson 20

Power Functions and Root Functions

How integer and rational exponents are defined, which inputs each power and root function accepts, how roots undo powers, and why the square root of x squared is the absolute value of x.

  • Theory part 39
  • Practice part 40
  • Quadratics, Circles, and Roots

A square with an area of 49 square meters has sides of 7 meters, and a cube that holds 64 cubic centimeters has edges of 4 centimeters. Squaring and taking a square root undo each other, and so do cubing and taking a cube root. For cubes the pairing is perfect. For squares it needs care, because 77 and −7-7 both square to 4949 and a root has to choose one answer.

Key terms

Power function

Definition A power function is a function of the form

f(x)=kxp,f(x) = kx^p,

where k≠0k \ne 0 is a real constant and the exponent pp is a rational constant, often an integer. Irrational exponents such as x2x^{\sqrt{2}} also give power functions for positive xx, but defining them needs the exponential functions of a later unit. The domain is the set of real xx for which xpx^p is a real number, and it depends on pp as described below. Some books use the name only for k=1k = 1.

In plain words The variable is raised to a fixed power and multiplied by a constant. The exponent alone decides most of the shape of the graph.

Example The area of a circle A(r)=πr2A(r) = \pi r^2 is a power function with k=πk = \pi and p=2p = 2. So are the volume of a ball V(r)=43πr3V(r) = \frac{4}{3}\pi r^3, the function 1x=x−1\frac{1}{x} = x^{-1} and the function x=x1/2\sqrt{x} = x^{1/2}. A polynomial such as x2+xx^2 + x is not a power function, because no single kxpkx^p agrees with it everywhere. It is 00 at x=−1x = -1, while a power function with k≠0k \ne 0 is never 00 away from x=0x = 0.

Integer exponents

Definition For a real number xx and a positive integer nn, the power xnx^n is the product of nn factors equal to xx. For x≠0x \ne 0 we also set

x0=1,x−n=1xn.x^0 = 1, \qquad x^{-n} = \frac{1}{x^n}.

The expression 000^0 is left undefined here, and 0−n0^{-n} would mean division by zero. So xnx^n with n≥1n \ge 1 has domain all real numbers, while x0x^0 and x−nx^{-n} have domain x≠0x \ne 0. Some formulas, such as the binomial theorem and the power rule of calculus, use the convention that x0=1x^0 = 1 for every xx, including x=0x = 0, and state it when they need it. When the integer exponent is even the function is even, so its graph is symmetric about the yy-axis, and its values are positive for x≠0x \ne 0. When the exponent is odd the function is odd, so its graph is symmetric about the origin, and each value has the sign of xx.

In plain words A positive integer exponent counts repeated factors. A negative one puts the power in the denominator, which is why zero is not allowed.

Example A few values show the patterns.

xxx2x^2x3x^3x−1x^{-1}x−2x^{-2}
−2-244−8-8−12-\frac{1}{2}14\frac{1}{4}
−1-111−1-1−1-111
12\frac{1}{2}14\frac{1}{4}18\frac{1}{8}2244
22448812\frac{1}{2}14\frac{1}{4}

Even exponents give the same value at xx and −x-x, odd exponents flip the sign, and negative exponents grow large in absolute value as xx approaches 00.

Principal root

Definition Let n≥2n \ge 2 be an integer and aa a real number.

  • If nn is odd, an\sqrt[n]{a} is the unique real number bb with bn=ab^n = a.
  • If nn is even and a≥0a \ge 0, an\sqrt[n]{a} is the unique real number b≥0b \ge 0 with bn=ab^n = a.
  • If nn is even and a<0a < 0, no real number bb has bn=ab^n = a, so an\sqrt[n]{a} is not a real number.

In the first two cases an\sqrt[n]{a} is called the principal nnth root of aa. For n=2n = 2 we write a\sqrt{a}.

In plain words A radical sign stands for one number, never two. For even roots it is the nonnegative one.

Example The number 44 has two square roots, 22 and −2-2, since both square to 44, but the symbol 4\sqrt{4} means 22 only. The cube root −273\sqrt[3]{-27} is −3-3, because (−3)3=−27(-3)^3 = -27. The fourth root 164\sqrt[4]{16} is 22, and −9\sqrt{-9} is not a real number.

Even and odd roots

Definition Let n≥2n \ge 2 be an integer and consider the root function f(x)=xnf(x) = \sqrt[n]{x}.

  • For even nn its domain and range are both [0,∞)[0, \infty).
  • For odd nn its domain and range are both all real numbers, and it is an odd function, −xn=−xn\sqrt[n]{-x} = -\sqrt[n]{x}.

In both cases the function is increasing on its domain.

In plain words You can take the cube root of any number, but a square root only of a number that is not negative. Odd roots keep the sign of what is under them.

Example The function 6−2x\sqrt{6 - 2x} needs 6−2x≥06 - 2x \ge 0, so its domain is x≤3x \le 3. The function 6−2x3\sqrt[3]{6 - 2x} is defined for every real xx. At x=7x = 7, for instance, it gives −83=−2\sqrt[3]{-8} = -2.

Rational exponents

Definition Let mn\frac{m}{n} be a rational number in lowest terms with integers mm and n≥2n \ge 2, and let aa be a real number for which an\sqrt[n]{a} is real, with a≠0a \ne 0 when m<0m < 0. Then

a1/n=an,am/n=(an)m=amn.\begin{gathered} a^{1/n} = \sqrt[n]{a}, \\[0.4em] a^{m/n} = \left(\sqrt[n]{a}\right)^m = \sqrt[n]{a^m}. \end{gathered}

For a>0a > 0 the usual laws aras=ar+sa^r a^s = a^{r + s}, (ar)s=ars(a^r)^s = a^{rs} and (ab)r=arbr(ab)^r = a^r b^r (with b>0b > 0 too) hold for all rational rr and ss. For a negative base the exponent must be written in lowest terms, and these laws can fail.

In plain words The denominator of the exponent is a root and the numerator is a power. Taking the root first keeps the numbers small.

Example Three quick evaluations.

82/3=(83)2=4,16−3/4=1(164)3=18,(−32)3/5=(−2)3=−8.\begin{gathered} 8^{2/3} = \left(\sqrt[3]{8}\right)^2 = 4, \\[0.4em] 16^{-3/4} = \frac{1}{\left(\sqrt[4]{16}\right)^3} = \frac{1}{8}, \\[0.8em] (-32)^{3/5} = (-2)^3 = -8. \end{gathered}

Lowest terms matter. The value of (−8)1/3(-8)^{1/3} is −2-2, but writing the exponent as 26\frac{2}{6} and computing ((−8)2)1/6=641/6\left((-8)^2\right)^{1/6} = 64^{1/6} gives 22, the wrong sign. That is why (ar)s=ars(a^r)^s = a^{rs} is only promised for a>0a > 0.

Domain of power and root functions

Definition For f(x)=xm/nf(x) = x^{m/n} with mn\frac{m}{n} in lowest terms, n≥2n \ge 2 and m≠0m \ne 0, the natural domain is given by this table.

Denominator nnm>0m > 0m<0m < 0
oddall real numbersx≠0x \ne 0
evenx≥0x \ge 0x>0x > 0

For a formula built from several pieces, every radicand of an even root must be nonnegative and every denominator must be nonzero.

In plain words An even root allows nothing negative under it. A negative exponent allows nothing that makes the denominator zero.

Example The function x2/3x^{2/3} accepts every real number, and at x=−8x = -8 it gives (−83)2=4\left(\sqrt[3]{-8}\right)^2 = 4. Some graphing calculators draw it only for x≥0x \ge 0, but by the definition above its graph also has a left half, the mirror image of the right half in the yy-axis. The function x3/2x^{3/2} needs x≥0x \ge 0, and x−1/2x^{-1/2} needs x>0x > 0. For

k(x)=(x−1)−1/4=1x−14k(x) = (x - 1)^{-1/4} = \frac{1}{\sqrt[4]{x - 1}}

the fourth root needs x−1≥0x - 1 \ge 0 and the division needs x−1≠0x - 1 \ne 0, so the domain is (1,∞)(1, \infty).

Inverse relationship

Definition Let n≥2n \ge 2 be an integer. If nn is odd, xnx^n is one-to-one on all real numbers and its inverse is xn\sqrt[n]{x}. If nn is even, xnx^n is not one-to-one on all real numbers, since (−x)n=xn(-x)^n = x^n, but its restriction to [0,∞)[0, \infty) is one-to-one with range [0,∞)[0, \infty), and the inverse of that restriction is xn\sqrt[n]{x}. Accordingly (xn)n=x\left(\sqrt[n]{x}\right)^n = x for every xx in the domain of the root, while xnn=x\sqrt[n]{x^n} = x holds for every real xx when nn is odd but only for x≥0x \ge 0 when nn is even. More generally, for a rational p≠0p \ne 0 the functions xpx^p and x1/px^{1/p} on (0,∞)(0, \infty) are inverses of each other.

In plain words A root undoes a power. For an even power this works only after you keep the right half of the graph, because the root can only answer with a nonnegative number. See inverse functions for the general idea.

Example The point (2,8)(2, 8) on y=x3y = x^3 matches the point (8,2)(8, 2) on y=x3y = \sqrt[3]{x}, and (2,16)(2, 16) on y=x4y = x^4 with x≥0x \ge 0 matches (16,2)(16, 2) on y=x4y = \sqrt[4]{x}. On (0,∞)(0, \infty) the functions x3/2x^{3/2} and x2/3x^{2/3} are inverses, and indeed 43/2=84^{3/2} = 8 while 82/3=48^{2/3} = 4.

The square root of a square

Definition For every real number xx,

x2=∣x∣.\sqrt{x^2} = \lvert x \rvert.

More generally, for an integer n≥2n \ge 2 the root xnn\sqrt[n]{x^n} equals ∣x∣\lvert x \rvert when nn is even and equals xx when nn is odd. In particular x2=x\sqrt{x^2} = x holds exactly when x≥0x \ge 0.

In plain words Squaring forgets the sign, and the square root cannot bring it back. It always answers with the nonnegative number.

Example For x=−5x = -5 the square root gives back 55, not −5-5.

(−5)2=25=5=∣−5∣.\sqrt{(-5)^2} = \sqrt{25} = 5 = \lvert -5 \rvert.

In the same way 9x2=3∣x∣\sqrt{9x^2} = 3\lvert x \rvert, and

x2−6x+9=(x−3)2=∣x−3∣.\begin{aligned} \sqrt{x^2 - 6x + 9} &= \sqrt{(x - 3)^2} \\[0.4em] &= \lvert x - 3 \rvert. \end{aligned}

At x=1x = 1 the left side is 4=2\sqrt{4} = 2, which matches ∣1−3∣=2\lvert 1 - 3 \rvert = 2, while the tempting answer x−3x - 3 would give −2-2.

Check yourself

  1. Evaluate 27−2/327^{-2/3} and (−27)2/3(-27)^{2/3}.
Show the answer

Take the root first.

27−2/3=1(273)2=19,(−27)2/3=(−273)2=(−3)2=9.\begin{gathered} 27^{-2/3} = \frac{1}{\left(\sqrt[3]{27}\right)^2} = \frac{1}{9}, \\[0.8em] (-27)^{2/3} = \left(\sqrt[3]{-27}\right)^2 = (-3)^2 = 9. \end{gathered}
  1. Find the domain of f(x)=4−x+(x+1)−1/3f(x) = \sqrt{4 - x} + (x + 1)^{-1/3}.
Show the answer

The square root needs 4−x≥04 - x \ge 0, so x≤4x \le 4. The cube root accepts every number, but the negative exponent puts x+13\sqrt[3]{x + 1} in a denominator, so x≠−1x \ne -1. The domain is (−∞,−1)∪(−1,4](-\infty, -1) \cup (-1, 4].

  1. Simplify 4x2+4x+1\sqrt{4x^2 + 4x + 1} so that the result is correct for every real xx.
Show the answer

Since 4x2+4x+1=(2x+1)24x^2 + 4x + 1 = (2x + 1)^2, the expression equals ∣2x+1∣\lvert 2x + 1 \rvert. At x=−1x = -1 the original gives 4−4+1=1\sqrt{4 - 4 + 1} = 1, which matches ∣−1∣=1\lvert -1 \rvert = 1, while 2x+12x + 1 would give −1-1.

How this lesson connects

Where this leads in Calculus