A dealer who sells a European claim on a stock wants to know how much money it takes to reproduce the claim exactly. Is there a portfolio of shares and cash, traded continuously with no money added or withdrawn, whose value equals the payoff at maturity on every path? If there is, its starting cost is the only price that leaves no arbitrage, and that cost does not depend on the stock’s expected return. This lesson builds the portfolio in the frictionless Black-Scholes market, derives the Black-Scholes PDE by matching its random and predictable parts with Itô’s formula, and states the terminal and boundary information that turn the equation into a pricing problem.
Key terms
Frictionless market assumptions
Definition The Black-Scholes market on a horizon has two traded assets. The money-market account is with a constant continuously compounded rate . The stock has an ex-dividend price with
under the physical measure , with a constant drift , a constant volatility , a starting price and a constant continuous dividend yield , so that one share pays cash at the rate . The filtration is the one generated by the single Brownian motion , and stock paths are continuous. The frictionless assumptions are that trading is continuous in time, any real number of shares may be held, short sales are allowed with full use of the proceeds, cash is lent and borrowed at the same rate , and there are no transaction costs, bid-ask spreads, taxes, margin limits or price impact. Trading strategies are predictable, satisfy the integrability that their stochastic integrals need, and are admissible. Admissibility is a technical restriction that rules out doubling strategies, for example a lower bound on the value or a square-integrability condition on the discounted gains under a pricing measure. The claim to be priced is European and pays at .
In plain words The model removes every reason for a hedge to fail except price risk itself. One Brownian motion drives the only risky price, trades cost nothing and can happen at every instant, and cash is available without limit at a single rate. These are hypotheses of the model, not a description of real markets, and removing any one of them changes the mathematics.
Example The constructed claim of the later cards pays , with , , and one year to maturity. At its hedge holds about shares worth and borrows in the cash account. If borrowing cost percentage points more than lending, carrying that loan would cost about more per year at current levels, and the single rate in the PDE would no longer describe the hedge. A proportional cost per share traded would make continuous rebalancing unaffordable, because the holding moves with the Brownian path and the total number of shares bought and sold over any time interval is infinite. Discrete rebalancing instead leaves a hedging error, studied in the lesson on discrete delta hedging.
Self-financing delta hedge
Definition A trading strategy holds shares and units of the money-market account, so its value is and its cash holding is . It is self-financing when
understood in integral form, with predictable and almost surely. The three terms are the gain on the shares, the dividends they receive and the interest on the cash holding, which is negative when cash is borrowed. This extends the discrete accounting of the lesson on self-financing portfolios. For strategies that are themselves Itô processes, the product rule gives
and the self-financing condition says that the last three terms add up to the dividends . Shares bought at the market price are paid for out of the cash account, so rebalancing by itself creates no gain. Given a pricing function with a continuous derivative , the delta hedge is the self-financing strategy that holds
shares and keeps the rest of its value in cash. Its Brownian part is , the same as the Brownian part of in Itô’s formula. The holding is chosen from the current time and price before the next Brownian increment, so it is predictable.
In plain words Self-financing means that nothing is added or taken out after the start. Purchases are paid from cash, sales and dividends go into cash, and cash earns or pays the rate . Holding shares makes the portfolio and the claim respond to the same small price move by the same amount.
Example For the constructed claim with , , and one year to maturity, the pricing function verified in the Black-Scholes PDE card is
At the value is and the hedge holds shares. Their value is , so the cash holding is , a loan. The claim and the hedge both have the Brownian coefficient currency units per square root of a year. A mistaken accounting that differentiates and books the term as a gain would count the purchase of shares as profit, although the cash paid for them leaves the same portfolio.
Replication argument
Definition Work under the frictionless assumptions with , and let have continuous derivatives , and on . Suppose a self-financing strategy has value for . Itô’s formula gives
with the derivatives at . The decomposition of a continuous Itô process into a part and a part is unique, so the coefficients can be compared with those of the self-financing equation. The coefficients give , and since the strategy must be the delta hedge. With that holding the coefficients give
The term appears on both sides and cancels, which leaves the Black-Scholes PDE along the path. For every the law of has a positive density on all of , so by continuity the PDE holds at every point of . Conversely, suppose is also continuous on , solves the PDE and satisfies . Then Itô’s formula and the PDE show that the delta hedge started with is self-financing with value at every , and this value tends to as . If the hedge and the opposite position are both admissible, no arbitrage forces the claim’s price at time to be . At any other price, buying the cheaper of the claim and the hedge and selling the dearer locks in the difference with no risk, because the two pay the same at . This lesson derives the PDE in this way and verifies a smooth example. A general existence theory for nonsmooth payoffs, and a general representation of every claim as a hedge, have further hypotheses and are stated as boundaries rather than proved.
In plain words Matching the random parts picks the hedge, and matching the predictable parts then gives an equation for the price. The stock’s expected return enters the claim and the hedge in exactly the same way, so it cancels. A forecast of the drift can matter for investing, but it cannot change a price that is fixed by replication.
Example For the constructed claim at one year before maturity, and . Take two analysts with the drift estimates and . The Itô drift of is and the drift of the hedge is , and both equal for every . That is per year for the first analyst and per year for the second. The two analysts disagree about how fast the claim’s value is expected to grow, but they compute the same price .
Black-Scholes PDE
Definition Under the frictionless assumptions with constants , and , the Black-Scholes PDE for a pricing function is
for and , with for a dividend-free stock. It is linear, second order and parabolic, it is solved backward from maturity, and its coefficients do not contain . The four terms are the time derivative in calendar time, the gamma term, the carry of the stock position at the rate and the financing of the claim’s value at the rate . In the log price , where and , the equation has constant coefficients,
the form from which numerical schemes and the reduction to the heat equation start.
In plain words Write theta for and gamma for . The equation says that theta plus times gamma equals , the interest on the hedge’s cash plus the dividends on its shares. Along a delta-hedged position, time decay and convexity together earn exactly what the hedge’s cash and dividends earn. With , a claim with positive gamma loses value as time passes at the rate .
Example The constructed function with has , and . With , , and , the four terms of the PDE are , , and , which are
and they add to zero. The same cancellation holds at every and every , since each term is a constant multiple of . Theta is per year, about per calendar day in a -day year.
Terminal condition
Definition The terminal condition of a European claim with payoff is for every , and the pricing function must approach it, as . For a call with strike the payoff is , and for a put it is . The PDE alone has many solutions, and the terminal condition selects the one that belongs to the contract. The data are given at the final time and the equation is solved toward earlier times. In the remaining time it becomes a forward parabolic equation with initial data , while prescribing the values at and solving forward in calendar time would be an ill-posed backward heat problem. A payoff need not be smooth. The call payoff has a kink at , so the smooth derivation is applied for , where the model’s call price is smooth when , and the payoff is reached as the limit at maturity. Weak and viscosity formulations handle nonsmooth problems without claiming classical derivatives everywhere, and they are not developed here.
In plain words The equation describes how a value changes, and the payoff says where it must end. Without the payoff the equation cannot tell a call from a forward contract or from a bond.
Example With , the functions , and all solve the PDE. For the first, . For the second, the time derivative cancels the financing term . Their terminal values are , and , the payoffs of a share, of a bond paying at and of the constructed claim. Because the PDE is linear, the difference is the solution with terminal value , a forward contract with delivery price . The constructed claim’s exponential factor equals at , so that function meets its payoff exactly at maturity.
Boundary conditions
Definition The Black-Scholes PDE is posed on the unbounded domain , and a GBM price started above zero never reaches zero or infinity in finite time. No boundary value is imposed in the classical sense. Instead, the solution is required to lie in a growth class, for example for constants and , which excludes solutions that grow too fast toward the edges of the domain. How such a growth class gives uniqueness is shown in the lesson on Feynman-Kac. The behavior near the edges then follows from the payoff. Setting in the equation removes the terms with derivatives in and leaves , which is consistent with the limits of a call and a put, where . For a call, as , and as
For a put, as and as . A numerical method on a truncated interval needs conditions at the artificial edges that agree with these limits, such as for a call, and the error from the truncation shrinks as the interval widens.
In plain words On the whole half-line there is no edge where the stock can be stopped, so the payoff and a growth condition carry all the information. Far below the strike a call is nearly worthless, and far above it a call is worth almost exactly the discounted stock less the discounted strike. A computer grid has to stop somewhere, and the values it imposes at its edges must match this behavior.
Example Take , , , and . A grid for the call that stops at sets the edge value
and a grid that stops at sets about . The exact call value from the formula of the lesson on the Black-Scholes formula differs from these edge values by about at and by less than at . For the put, the edge value at is , the discounted strike.
Check yourself
- With , , , and , show that solves the Black-Scholes PDE with dividends and has terminal value . Find its value, its delta hedge and its cash holding, and compare the value with the forward price.
Show the answer
Since , the derivatives are , and . Substituting,
and at the function equals . The value is . The hedge holds shares and has the cash holding . The forward price is , the delivery price that would make this value zero. Here the delivery price is above it, so the long position has negative value. The value of an existing forward and the forward price are different quantities. As increases the share holding rises toward , and the dividends received pay for exactly those extra shares, so the loan only accrues interest.
- For the constructed claim paying with , and , the stock now pays a continuous dividend yield . Find the constant for which solves the PDE, and the value at . A classmate keeps the dividend-free value . Which part of the hedge’s accounting was left out, and what residual does the dividend-free function leave in the new PDE?
Show the answer
For this function , and , so the PDE requires , that is
The value at is . The classmate left out the dividend cash that the hedge’s shares receive. Including it changes the coefficient of from to . In the dividend PDE, the dividend-free function gives per year instead of zero.
- Suppose and , so the stock is riskless with . Why does the matching of Brownian coefficients no longer determine the hedge? Show that allows an arbitrage, and for find the value of a call with , and .
Show the answer
With both the claim and every portfolio have zero Brownian coefficient, so the first matching step holds for every and fixes nothing. The step that divides by fails, and the stock is a second riskless asset. If , borrow at the rate and buy one share. At the share is worth and the loan , a sure gain at zero cost, for example with and . If , the reverse trade gains. With the terminal price is for certain, so the call pays for certain and is worth
Wherever it is differentiable, this function solves , the PDE with .