A trader buys a one-year option at its Black-Scholes price, sells the model delta in shares and plans to adjust the hedge once a day. Between two trading dates the share holding stays fixed while the option’s delta moves with the stock, so the hedged position gains or loses money even when the model’s volatility is right. How large is that residual, which sign does it have, and how does it depend on the size of the realized move? This lesson derives the leading term of the one-step residual, shows why it remains random on every finite grid, and relates the accumulated error to a comparison of realized and model variance weighted by gamma.
Key terms
Discrete delta hedging
Definition Fix trading dates with steps . Let be the Black-Scholes price of a European option computed with a model volatility and constant and , with Greeks , and . A discrete delta hedge of a long option holds the option, is short shares on , and keeps the balance in the money-market account, so that the option, the shares and this cash are worth zero together at , with earlier gains set aside in the same account. The holding is chosen from the information at and is not changed inside the step. The one-step residual is the change in value of this position over . With , writing , and , it is
With and nonzero it also contains the interest on the cash balance and the dividends owed on the short shares. For the price is smooth, and a second-order Taylor expansion with the state frozen at gives . The short shares cancel the delta term, and the carry adds about . The model pricing PDE then leaves
The omitted terms, such as and the mixed term , are of higher order for small steps, but they matter for large moves and near expiry close to the strike, where the derivatives change quickly. A short option with the opposite share position has every sign reversed.
In plain words The hedge removes the first-order exposure to the stock at each trading date and then sits still. Over the step, the option’s curvature earns half gamma times the squared move, while time decay charges half gamma times the squared move the model expects. The residual is the gap between the two.
Example Take a constructed hedged long option with , per currency unit, and , rebalanced daily with year. The model charge is
in squared currency units. A move of gives the leading residual , a move of gives , and no move gives .
Gamma exposure
Definition The gamma exposure of a position is its second derivative in the stock price, for one long option and for one short option, in units of shares per currency unit. The delta hedge has zero gamma, so the gamma of the hedged position is that of the option. In the leading residual it multiplies the excess of the squared move over the model charge, and in terms of the return
where the cash gamma is in currency per unit of squared return. Gamma also sets the size of the next trade, since the new delta is to first order. For a long call or put, , so after a rise the hedger shorts more shares at the higher price and after a fall buys shares back at the lower price.
In plain words Gamma says how much the hedge ratio moves when the stock moves. A long gamma position profits from large moves and pays for this through time decay, and a short gamma position collects the time decay and loses on large moves.
Example In the constructed example the cash gamma is , so a squared daily return of , a one percent move, contributes , against the model charge . For the at-the-money Black-Scholes call with , , and , where , a one-day rise to raises the delta by about and a fall to lowers it by about , close to .
Realized variance
Definition On the grid, the realized variance of the stock over is the sum of squared returns
or the same sum with log returns , and is its annualized version. Suppose that under the stock follows with an actual volatility and constant . Then, given and with , the squared move over a step of length satisfies
where the exact mean is and the drift enters only at order . The variance comes from with . As the mesh tends to zero, the realized variance tends in probability to the quadratic variation of , and for an adapted volatility process to , as in Quadratic variation and stochastic limits.
In plain words Realized variance adds up what the squared moves actually were. One squared move is a noisy reading, with a standard deviation larger than its mean, but many small ones add up to the variance rate times the elapsed time.
Example Five constructed daily returns of , , , and have squared sum . With this is an annualized variance of , a realized volatility of about , against the model variance for . At a volatility of one squared daily return has mean and standard deviation about , so a single day says little about the variance rate.
Hedging error
Definition The hedging error of the strategy is the value at of the position that buys the option at its model price at time , holds the delta hedge and the cash account until , and receives the payoff. It equals the residuals accrued to ,
with for exact replication, and an option writer who sells at the model price and holds the opposite hedge has the error . With it is for a call. Under the diffusion of the previous card, the frozen-state approximations give for one step
A price jump inside a step leaves the exact residual
which is nonnegative for a long call or put because is convex in , and which can be far from for a large jump. A single stock position cannot offset jumps of every size, and a random volatility leaves a vega exposure. These are separate sources of error from the squared-move residual of a diffusion.
In plain words The hedging error is what is left at maturity after the hedge has done its job, positive when the long-option hedger ends with a gain. On a finite grid it is a random quantity even in a correct model, and its average depends on whether the stock moved more or less than the model assumed.
Example For the constructed daily step with , , and an actual volatility , the expected squared move is against the model charge , so
with a standard deviation of about for the same step. A deliberately large constructed move of gives the leading estimate , which is only a second-order estimate. Repricing the at-the-money Black-Scholes call of the gamma exposure card gives an exact residual of for a rise of in one day and for a fall of , while its leading term is for both.
Trading frequency
Definition The trading frequency is the number of rebalancing dates per unit of time, on an equally spaced grid. Over a fixed horizon with steps and the state frozen, the one-step noise has standard deviation about , and the conditionally uncorrelated steps add up to
so more frequent trading reduces the noise like and leaves the variance mismatch unchanged. For calls and puts on an equally spaced grid with , the root mean square of the total error shrinks in proportion to , a result stated here without proof. Trading has costs. With a proportional cost per unit of traded value, a rebalance trades about shares and costs about on average, so the total cost over the horizon grows like . Letting with a fixed is therefore a different economic model from frictionless continuous trading, and choosing the trading frequency against costs is a separate optimization problem.
In plain words Trading more often makes each unhedged interval shorter, so the random part of the error averages out better. It does not remove the error from using the wrong volatility, and every extra trade pays costs.
Example With the frozen constructed values , and over one year, daily trading gives , and four trades a day halve it to about . A constructed simulation of paths of the at-the-money one-year call with , zero drift and gave standard deviations of about , and for , and rebalances, halving with every fourfold increase, and means within sampling error of zero. With a cost of on every share traded, including the first purchase and the final unwind, the mean costs were about , and .
Gamma-weighted variance comparison
Definition Summing the leading residuals with gives
with , a comparison of each realized squared return with the model variance, weighted by the cash gamma at that date. For continuous hedging the comparison is exact under these assumptions. Trading is frictionless and continuous, under the stock follows with adapted and , the long option is hedged by a short position of shares computed from the model with constant , and , cash earns , and the dividends owed on the short shares are paid from cash. Itô’s formula for uses , the model PDE uses , and the difference of the two drifts gives
for calls and puts, applying Itô on and letting . With and at all times the continuous hedge gains on every path, and with it loses. The amount depends on the path through , which is largest near the strike close to expiry. On a finite grid the random squared-shock noise of the previous cards comes on top.
In plain words The hedger effectively buys variance at the model rate and receives the realized rate, in amounts set by the cash gamma at each moment. Realized variance above the model rate helps a long gamma position, and the help counts most where gamma is large. It is not a guaranteed gain from owning an option, because realized variance can fall short and because the weights depend on where the stock goes.
Example For the five constructed daily returns of the realized variance card, with held fixed, and the stock starting at , the leading residuals are about , , , and , which add to about . In the simulation of the previous card with in place of , the mean error was about for every trading frequency, with standard deviations of about , and for , and rebalances, which do not shrink to zero. With zero drift and the stock gains of the hedge have mean zero on every grid, so the exact mean error is .
Check yourself
- A trader is short an option and delta hedged with shares, so the position gamma is per currency unit. The stock is at , the model volatility is , the actual volatility is and the hedge is rebalanced weekly, . Find the expected leading residual for one week and the leading residual for a weekly move of , and explain the signs.
Show the answer
The model charge is , and the expected squared move is . With ,
The short gamma position gains on average because the stock is expected to move less than the model charge assumes. For a move of the residual is , a loss, because the squared move exceeds the model charge. That move is about weekly standard deviations, since . Both numbers are second-order estimates.
- A colleague says that if the actual volatility equals the model volatility, a daily delta hedge has no error. Using the frozen values , , and , find the standard deviation of one daily residual and of the accumulated error over one year, and the effect of trading four times as often. What would happen to the mean error with ?
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The mean of the leading residual is zero, but its standard deviation is
since . Over conditionally uncorrelated days the standard deviation grows to about . With four trades a day each residual is four times smaller and there are four times as many, so the total standard deviation is multiplied by , giving about . The colleague is right only about the mean. With the frozen mean error over the year is at every trading frequency, so more frequent trading would not remove it.
- For the at-the-money Black-Scholes call with , , and , where and , a hedger is long the call and short shares. Over one day the stock moves by or by . Compare the leading residual with the exact residual, and explain why the two exact values differ.
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The leading term is the same for both moves,
Repricing gives for the rise and for the fall. Both exact residuals are positive, because for a move this large the convexity gain far exceeds the one-day time decay . They differ because the expansion stops at second order. The third derivative here is , since gamma falls as the stock rises above this level. Its term is about for the rise and for the fall, which brings the estimates to about and , and higher-order terms account for the rest. A move of in one day is almost eight daily standard deviations at the model volatility , so the leading term shows the sign but should not be read as the exact hedge result.