Unit 1, lesson 6

Cylinders and Quadric Surfaces

How to picture a surface in space from its traces, and how to recognize cylinders and the standard quadric surfaces from the signs and shifts in their equations.

  • Theory part 11
  • Practice part 12
  • Surfaces and Coordinate Systems

Slice a loaf of bread and every slice shows a cross section. Stack the slices back up in your mind and you have the loaf again. That is exactly how to see a surface from its equation. Fix one coordinate, look at the curve that is left, then let the slice move. A handful of shapes, the quadric surfaces, cover every second degree equation you will meet in this course, and they come back later as graphs, level surfaces and boundaries of solids.

Key terms

Traces

Definition The trace of a surface SS in a plane is the intersection of SS with that plane. For a surface given by an equation in xx, yy and zz, the trace in the horizontal plane z=kz = k is found by substituting z=kz = k, which leaves an equation in xx and yy describing a curve in that plane. Traces in the planes x=kx = k and y=ky = k are found the same way. A trace can be a curve, a point, a pair of lines, or empty.

In plain words A trace is the cut you see when a flat sheet slices through the surface. Watching how the cuts change as kk moves tells you the shape.

Example For z=x2+y2z = x^2 + y^2, the table lists a few traces.

PlaneTrace equationTrace
z=4z = 4x2+y2=4x^2 + y^2 = 4circle of radius 22 at height 44
z=0z = 0x2+y2=0x^2 + y^2 = 0the single point (0,0,0)(0, 0, 0)
z=−1z = -1x2+y2=−1x^2 + y^2 = -1empty
x=0x = 0z=y2z = y^2parabola in the yzyz plane

The horizontal circles grow as kk grows, and the vertical traces are parabolas, so the surface is a bowl.

Cylinders

Definition Let CC be a curve in a plane and let ℓ\ell be a line not parallel to that plane. The cylinder through CC with rulings parallel to ℓ\ell is the union of all lines parallel to ℓ\ell that pass through a point of CC. In particular, if an equation in xx, yy and zz does not contain zz, it describes a cylinder with rulings parallel to the zz axis. A point (x,y,z)(x, y, z) lies on it exactly when (x,y)(x, y) satisfies the equation, whatever zz is. The same holds with the roles of the variables exchanged.

In plain words A missing variable is free. Draw the curve in the plane of the other two variables and slide it along the missing axis.

Example In space, x2+y2=1x^2 + y^2 = 1 is not a circle. It is the circular cylinder of radius 11 around the zz axis, since every horizontal trace is the same unit circle. The equation y=x2y = x^2 is a parabolic cylinder with rulings parallel to the zz axis, and x2+z2=9x^2 + z^2 = 9 is a circular cylinder of radius 33 around the yy axis.

Ellipsoids

Definition For constants a,b,c>0a, b, c > 0, the surface

x2a2+y2b2+z2c2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1

is an ellipsoid centered at the origin. It meets the axes at (±a,0,0)(\pm a, 0, 0), (0,±b,0)(0, \pm b, 0) and (0,0,±c)(0, 0, \pm c). Its trace in z=kz = k is an ellipse for ∣k∣<c\lvert k \rvert < c, a single point for ∣k∣=c\lvert k \rvert = c, and empty for ∣k∣>c\lvert k \rvert > c, and the same pattern holds in the other directions. When a=b=ca = b = c it is a sphere of radius aa.

In plain words An ellipsoid is a squashed or stretched ball. All three squares have plus signs, so the surface is bounded.

Example Take x24+y29+z2=1\frac{x^2}{4} + \frac{y^2}{9} + z^2 = 1. At height z=12z = \frac{1}{2} the trace satisfies x24+y29=34\frac{x^2}{4} + \frac{y^2}{9} = \frac{3}{4}, which rearranges to

x23+y227/4=1,\frac{x^2}{3} + \frac{y^2}{27/4} = 1,

an ellipse with semi-axes 3≈1.73\sqrt{3} \approx 1.73 and 332≈2.60\frac{3\sqrt{3}}{2} \approx 2.60. At z=1z = 1 the trace shrinks to the point (0,0,1)(0, 0, 1), and above that there is nothing.

Elliptic and hyperbolic paraboloids

Definition For constants a,b>0a, b > 0 and c≠0c \ne 0, the elliptic paraboloid and the hyperbolic paraboloid with vertex at the origin are

zc=x2a2+y2b2,zc=x2a2−y2b2.\frac{z}{c} = \frac{x^2}{a^2} + \frac{y^2}{b^2}, \qquad \frac{z}{c} = \frac{x^2}{a^2} - \frac{y^2}{b^2}.

The elliptic one has horizontal traces that are ellipses on the side where z/c>0z/c > 0, the vertex alone at z=0z = 0, nothing on the other side, and parabolas as vertical traces. It opens upward when c>0c > 0 and downward when c<0c < 0. The hyperbolic one has hyperbolas as traces in z=kz = k for k≠0k \ne 0, the pair of lines y=±baxy = \pm \frac{b}{a} x for k=0k = 0, and parabolas opening in opposite directions in the planes x=kx = k and y=ky = k. Its shape near the origin is a saddle.

In plain words One variable appears to the first power and two are squared. Same signs on the squares give a bowl, opposite signs give a saddle.

Example For z=y2−x2z = y^2 - x^2, the trace x=0x = 0 is z=y2z = y^2, opening upward, and the trace y=0y = 0 is z=−x2z = -x^2, opening downward. So the origin is a low point along the yy direction and a high point along the xx direction. The trace z=1z = 1 is the hyperbola y2−x2=1y^2 - x^2 = 1, the trace z=−1z = -1 is x2−y2=1x^2 - y^2 = 1, and z=0z = 0 gives the crossing lines y=xy = x and y=−xy = -x.

Cones

Definition For constants a,b,c>0a, b, c > 0, the elliptic cone with vertex at the origin and axis along the zz axis is

x2a2+y2b2=z2c2.\frac{x^2}{a^2} + \frac{y^2}{b^2} = \frac{z^2}{c^2}.

Its traces in z=kz = k are ellipses for k≠0k \ne 0 and the single point at the origin for k=0k = 0. Its traces in x=0x = 0 and y=0y = 0 are pairs of lines through the origin. If a point (x,y,z)(x, y, z) lies on the cone, so does (tx,ty,tz)(tx, ty, tz) for every real tt, so the cone is a union of lines through its vertex.

In plain words Two ice cream cones joined at their tips. With every term on one side the constant is zero, and that zero is why the surface pinches to a single vertex.

Example For z2=x2+y2z^2 = x^2 + y^2, the trace z=2z = 2 is the circle x2+y2=4x^2 + y^2 = 4 of radius 22, and the trace y=0y = 0 is z2=x2z^2 = x^2, the lines z=xz = x and z=−xz = -x. The radius at height kk is ∣k∣\lvert k \rvert, so the sides rise at 45∘45^\circ.

Hyperboloids of one and two sheets

Definition For constants a,b,c>0a, b, c > 0, the hyperboloid of one sheet and the hyperboloid of two sheets with axis along the zz axis are

x2a2+y2b2−z2c2=1,z2c2−x2a2−y2b2=1.\begin{gathered} \frac{x^2}{a^2} + \frac{y^2}{b^2} - \frac{z^2}{c^2} = 1, \\[0.6em] \frac{z^2}{c^2} - \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1. \end{gathered}

With the right side equal to 11, one minus sign on the left gives one sheet and two minus signs give two sheets, and the axis belongs to the variable whose sign differs from the other two. On the one-sheet surface every trace z=kz = k is an ellipse, never empty, so the surface is one connected piece. On the two-sheet surface the trace z=kz = k satisfies x2a2+y2b2=k2c2−1\frac{x^2}{a^2} + \frac{y^2}{b^2} = \frac{k^2}{c^2} - 1, which is empty for ∣k∣<c\lvert k \rvert < c, so the surface splits into two pieces.

In plain words One sheet looks like a cooling tower with a narrow waist. Two sheets look like two bowls facing away from each other with a gap between them.

Example Compare x2+y2−z2=1x^2 + y^2 - z^2 = 1, the cone x2+y2−z2=0x^2 + y^2 - z^2 = 0 and x2+y2−z2=−1x^2 + y^2 - z^2 = -1. Each horizontal trace is a circle centered on the zz axis, a single point or empty. The table gives the radius at height z=kz = k.

Height kkOne sheetConeTwo sheets
0011pointempty
112\sqrt{2}11point
225\sqrt{5}223\sqrt{3}

The cone sits between the two hyperboloids at every height.

Translations

Definition Replacing xx, yy and zz in an equation by x−x0x - x_0, y−y0y - y_0 and z−z0z - z_0 moves the surface by the vector ⟨x0,y0,z0⟩\langle x_0, y_0, z_0 \rangle without changing its shape. A center, vertex or axis moves the same way. To recognize a shifted surface, complete the square in each variable that appears both squared and to the first power.

In plain words Linear terms next to squared terms mean the surface has been moved. Completing the square tells you where to.

Example Start from x2+4y2−z2−2x+8y+4z+1=0x^2 + 4y^2 - z^2 - 2x + 8y + 4z + 1 = 0. Completing the squares,

x2−2x=(x−1)2−1,4y2+8y=4(y+1)2−4,−z2+4z=−(z−2)2+4.\begin{aligned} x^2 - 2x &= (x - 1)^2 - 1, \\[0.4em] 4y^2 + 8y &= 4(y + 1)^2 - 4, \\[0.4em] -z^2 + 4z &= -(z - 2)^2 + 4. \end{aligned}

The constants add up to −1−4+4+1=0-1 - 4 + 4 + 1 = 0, so the equation becomes

(x−1)2+4(y+1)2=(z−2)2.(x - 1)^2 + 4(y + 1)^2 = (z - 2)^2.

This is an elliptic cone with vertex (1,−1,2)(1, -1, 2) and axis the vertical line x=1x = 1, y=−1y = -1.

Identifying surfaces

Definition A quadric surface is the set of points satisfying a second degree equation in xx, yy and zz. This lesson treats equations with no cross terms such as xyxy, yzyz or xzxz. Cross terms can be removed by rotating the axes, which is not needed here. An equation without cross terms can be identified as follows.

  1. If a variable is missing, the surface is a cylinder over the curve in the other two variables.
  2. Complete the square in every variable that appears both squared and to the first power.
  3. If all three variables are squared, move the constant to the right side, and if it is not zero, divide by it so the right side is 11. With right side 11, no minus signs on the left give an ellipsoid, one minus sign a hyperboloid of one sheet, two minus signs a hyperboloid of two sheets, and three minus signs the empty set. With right side 00, mixed signs give a cone and equal signs give only the center point.
  4. If two variables are squared and the third appears only to the first power, the surface is an elliptic paraboloid when the squares have equal signs and a hyperbolic paraboloid when they have opposite signs.
  5. If only one variable is squared and another appears to the first power, the surface is a parabolic cylinder, as in z=x2z = x^2 or x2=y+zx^2 = y + z.

Degenerate cases also occur. The equation x2+y2+z2=−1x^2 + y^2 + z^2 = -1 has no points, x2+y2+z2=0x^2 + y^2 + z^2 = 0 is a single point, x2+y2=0x^2 + y^2 = 0 is the zz axis, x2−y2=0x^2 - y^2 = 0 is the pair of planes y=xy = x and y=−xy = -x, and x2=1x^2 = 1 is the pair of parallel planes x=1x = 1 and x=−1x = -1.

In plain words Count the squares, check their signs, and look at the constant on the right. A quick trace then confirms the answer.

Example Take 4x2−y2+2z2+4=04x^2 - y^2 + 2z^2 + 4 = 0. Moving 44 to the right and dividing by −4-4 gives

y24−x2−z22=1.\frac{y^2}{4} - x^2 - \frac{z^2}{2} = 1.

There are two minus signs, so this is a hyperboloid of two sheets, and the odd sign out belongs to yy, so its axis is the yy axis. To confirm, the trace y=ky = k is x2+z22=k24−1x^2 + \frac{z^2}{2} = \frac{k^2}{4} - 1, which is empty when ∣k∣<2\lvert k \rvert < 2, leaving a gap between the two sheets.

Check yourself

  1. Identify x2−y2+z2−4z=0x^2 - y^2 + z^2 - 4z = 0 and give its center and axis.
Show the answer

Completing the square gives x2−y2+(z−2)2=4x^2 - y^2 + (z - 2)^2 = 4, so

x24−y24+(z−2)24=1.\frac{x^2}{4} - \frac{y^2}{4} + \frac{(z - 2)^2}{4} = 1.

There is one minus sign, so it is a hyperboloid of one sheet. The center is (0,0,2)(0, 0, 2) and the axis is the line x=0x = 0, z=2z = 2, parallel to the yy axis.

  1. Identify 9x2+4y2−36z=09x^2 + 4y^2 - 36z = 0 and describe its trace in the plane z=1z = 1.
Show the answer

Dividing by 3636 gives z=x24+y29z = \frac{x^2}{4} + \frac{y^2}{9}, an elliptic paraboloid with vertex at the origin opening upward. The trace z=1z = 1 is the ellipse x24+y29=1\frac{x^2}{4} + \frac{y^2}{9} = 1 with semi-axes 22 and 33.

  1. What sets in space do x2+2y2=0x^2 + 2y^2 = 0 and x2+2y2+z2=−1x^2 + 2y^2 + z^2 = -1 describe?
Show the answer

The first forces x=0x = 0 and y=0y = 0 with zz free, so it is the zz axis, a degenerate cylinder. The second has no solutions, because the left side is never negative, so it is the empty set.

How this lesson connects

It also uses Coordinate planes, equations of conic sections, completing the square and square roots.