Unit 10, lesson 78

Exposure netting and collateral dynamics

How signed portfolio values become positive exposure, how netting sets lower exposure through the netting inequality, how a signed collateral balance follows margin rules, and what the margin period of risk adds.

  • Video 78
  • Counterparty exposure and valuation adjustments

Three swaps with one counterparty are worth 1212, −9-9 and 44 million currency units to us. If the counterparty defaults, is the claim at risk 77 million or 1616 million, and how much of it is covered by collateral when the last margin call came days before the closeout? This lesson defines the signed portfolio value and positive exposure, proves that netting never raises exposure, treats collateral as a signed balance updated by a threshold and a minimum transfer amount, and follows one margin sequence through the margin period of risk to closeout. Which trades may be netted is a legal question, and the lesson takes the answer as an input.

Key terms

Signed portfolio value

Definition Fix one counterparty and a closeout valuation convention. For trade ii with that counterparty, let Vi(t)V_i(t) be its closeout value at time tt seen from our side, in currency units. It is the value at tt of the trade’s remaining cash flows, together with any contractual amounts that fell due and were not paid, positive when the trade is an asset to us and negative when it is a liability. For a group SS of trades, the signed portfolio value is

VS(t)=∑i∈SVi(t),V_S(t) = \sum_{i \in S} V_i(t),

and the same trades have the signed value −VS(t)-V_S(t) from the counterparty’s side. At a future date VS(t)V_S(t) is a random variable whose law depends on the measure in use, a pricing measure Q\mathbb{Q} for valuation adjustments or the physical measure P\mathbb{P} for risk limits. Which closeout value applies, for example a default-free value or a replacement value that includes the charges of a new counterparty, is a contractual convention that has to be stated.

In plain words A positive value means the counterparty owes us on net, and a negative value means we owe it. The sign is what makes netting and collateral calculations work, since obligations in opposite directions can cancel only if both keep their signs.

Example Three constructed trades have values 1212, −9-9 and 44 million currency units from our side, so their signed sum is 77 million. From the counterparty’s side the same trades are worth −12-12, 99 and −4-4 million, a sum of −7-7 million. The trade worth −9-9 million is an obligation of ours, not a loss.

Positive exposure

Definition Let VtV_t be the signed value of trades that are settled as a single claim at closeout. Without collateral, the exposure at tt is

Et=Vt+=max⁡(Vt,0),E_t = V_t^{+} = \max(V_t, 0),

the amount we stand to lose if the counterparty defaults at tt and pays nothing on the claim, before any recovery. A negative value gives zero exposure, because we would then owe the closeout amount to the counterparty and have no credit loss on these trades. With a usable collateral balance CtC_t, described in a later card, the residual exposure is (Vt−Ct)+(V_t - C_t)^{+}. At a future date the exposure is random, and its mean under a stated measure, E[(Vt−Ct)+]\mathbb{E}[(V_t - C_t)^{+}], is the expected exposure at tt. The positive part is convex, so Jensen’s inequality gives

E[(Vt−Ct)+]≥(E[Vt]−E[Ct])+,\begin{aligned} &\mathbb{E}\bigl[(V_t - C_t)^{+}\bigr] \\[0.4em] &\quad \ge \bigl(\mathbb{E}[V_t] - \mathbb{E}[C_t]\bigr)^{+}, \end{aligned}

often with strict inequality. The positive part has to be taken in each scenario, for example on each path of a Monte Carlo simulation, before averaging.

In plain words Exposure is what the counterparty would owe us at the moment it defaults. Only a positive amount owed is at risk, so a portfolio whose value is negative today still has exposure in the future scenarios where its value turns positive.

Example For the three trades settled as one claim, the exposure is 7+=77^{+} = 7 million. Suppose a constructed value at a future date is 1010 million or −10-10 million with probability 12\tfrac12 each. Its mean is 00, so the positive part of the mean is 00, while the expected exposure is 12⋅10=5\tfrac12 \cdot 10 = 5 million.

Netting set

Definition A netting set is a group of trades with one counterparty whose obligations are assumed to be offset into a single net claim at closeout under an enforceable netting agreement. A trade covered by no such agreement forms a netting set of its own. With disjoint netting sets S1,…,SKS_1, \dots, S_K and no collateral, the exposure is

Et=∑k=1K(∑i∈SkVi(t))+,E_t = \sum_{k=1}^{K} \Bigl(\sum_{i \in S_k} V_i(t)\Bigr)^{+},

so values are added inside a set before the positive part is taken, and positive parts are added across sets. Whether an agreement is enforceable in a given jurisdiction is a legal question. The model takes the grouping as an input and draws no legal conclusion from it. A collateral balance belongs to the agreement that governs it and reduces exposure only in the netting set that agreement covers, so one balance cannot be counted in full against two separate sets.

In plain words A netting set marks the trades whose payments may cancel when the counterparty defaults. Between different sets nothing cancels, so a liability in one set does not reduce a claim in another.

Example If all three trades are in one set, the exposure is (12−9+4)+=7(12 - 9 + 4)^{+} = 7 million. If the trade worth −9-9 million sits in a separate set, the exposure is (12+4)++(−9)+=16(12 + 4)^{+} + (-9)^{+} = 16 million, the same as with no netting at all. The marks are unchanged and we still owe 99 million on the separate trade, but that obligation no longer offsets the claim of 1616 million.

Netting inequality

Definition For any real numbers V1,…,VmV_1, \dots, V_m,

Enet=(∑i=1mVi)+≤∑i=1mVi+=Egross.\begin{aligned} E_{\text{net}} &= \Bigl(\sum_{i=1}^{m} V_i\Bigr)^{+} \\[0.4em] &\le \sum_{i=1}^{m} V_i^{+} = E_{\text{gross}} . \end{aligned}

Each value satisfies Vi≤Vi+V_i \le V_i^{+}, so ∑iVi≤∑iVi+\sum_i V_i \le \sum_i V_i^{+}, and the right side is nonnegative. The positive part of the sum is either the sum itself or 00, and both are at most ∑iVi+\sum_i V_i^{+}, which proves the inequality. Equality holds exactly when the values do not include both a strictly positive and a strictly negative entry. If they include one of each and the sum is nonnegative, the negative entry makes the sum strictly smaller than the sum of positive parts, and if the sum is negative, its positive part is 00 while the sum of positive parts is positive. The inequality holds scenario by scenario, so it also holds for expected exposures at every date. Applied to subtotals it shows that merging two netting sets never raises exposure, (A+B)+≤A++B+(A + B)^{+} \le A^{+} + B^{+}, and applied to the values −Vi-V_i it shows that netting also lowers the counterparty’s exposure to us. It compares groupings of the same trades at the same values.

In plain words Offsetting before taking the positive part can only help, because a negative value can cancel part of a positive one but never adds to the claim. When all values have the same sign, nothing cancels and netting changes nothing.

Example For 1212, −9-9 and 44 million, Enet=7E_{\text{net}} = 7 million and Egross=16E_{\text{gross}} = 16 million, so netting removes 99 million of exposure. From the counterparty’s side the netted exposure is (−7)+=0(-7)^{+} = 0 against a gross exposure of 99 million. If the second value were 99 million instead of −9-9 million, both measures would equal 2525 million.

Signed collateral balance

Definition The signed collateral balance CtC_t is the value in currency units, after haircuts, of the collateral that is usable at closeout, positive when we hold collateral from the counterparty and negative when we have posted collateral to it. Eligibility, haircuts, segregation and the right to use collateral decide how much counts, so they belong in the definition of CtC_t. If CtC_t can be applied immediately at closeout, the residual exposure is

Et=(Vt−Ct)+.E_t = (V_t - C_t)^{+} .

Held collateral lowers the claim. Posted collateral that is not segregated adds to it, since a defaulting counterparty may not return it. Variation margin follows the current mark. Initial margin is meant to cover adverse moves over a future closeout period and is often segregated, so it may not be available for ordinary use. This lesson uses a one-sided variation margin rule with threshold H≥0H \ge 0 and minimum transfer amount M>0M > 0, under which only the counterparty posts. At a margin date with balance Ct−C_{t^-} before the call, the target is

Ct∗=(Vt−H)+.C^{*}_t = (V_t - H)^{+} .

If ∣Ct∗−Ct−∣≥M\lvert C^{*}_t - C_{t^-} \rvert \ge M, a transfer brings the balance to the target, and otherwise the balance stays at Ct−C_{t^-}. The steps come in this order, first the target, then the comparison, then the transfer. A two-sided agreement adds the mirror rule for collateral we post, with target (Vt−H)+−(−Vt−H′)+(V_t - H)^{+} - (-V_t - H')^{+}, where H′H' is the threshold that applies to us. Because small transfers are skipped, CtC_t depends on the path of past marks, and the residual exposure depends on the joint path of VV and CC. If Ct>VtC_t > V_t, the exposure is 00, but the excess Ct−VtC_t - V_t is owed back to the counterparty, an obligation that still matters for our own credit risk and funding.

In plain words Collateral is a running balance that follows the mark with a lag and a dead zone. The threshold leaves a fixed slice of value unsecured, the minimum transfer amount ignores small changes, and the balance remembers the last call that was actually made.

Example For the three netted trades, V=7V = 7 million, the threshold is H=3H = 3 million, the minimum transfer amount is M=1M = 1 million and we hold 22 million. The target is (7−3)+=4(7 - 3)^{+} = 4 million, the requested transfer of 22 million is at least MM, so the counterparty posts it, the balance becomes 44 million and the exposure is 7−4=37 - 4 = 3 million. At the next margin date the mark is 7.47.4 million and the target 4.44.4 million, but the request of 0.40.4 million is below MM, so nothing moves and the exposure is 3.43.4 million. Had the first call been made at a mark of 7.47.4 million, the balance would be 4.44.4 million and the exposure 33 million, so the same mark leaves different exposures on different paths.

Margin period of risk

Definition A margin call protects against the mark at the time of the call and does not freeze the future value. The margin period of risk δ>0\delta > 0 is the modeled time from the last margin call that is effectively met to the closeout after a default, during which no further collateral arrives. Under the convention that the balance stays at CtC_t throughout, the gap exposure is

Et,δ=(Vt+δ−Ct)+,E_{t,\delta} = \bigl(V_{t+\delta} - C_t\bigr)^{+},

where Vt+δV_{t+\delta} is the closeout value at the end of the period and includes, consistently with the contract, the coupons, interest and other cash flows that fall due or go unpaid during it. Even with Ct=VtC_t = V_t, a rise of the value during the period creates exposure. Suppose that, given the information Ft\mathcal{F}_t, the change Vt+δ−VtV_{t+\delta} - V_t is normal with mean 00 and standard deviation s=σVδs = \sigma_V \sqrt{\delta}, where σV\sigma_V is a value volatility in currency units per square root of a year and δ\delta is in years. Then

E[(Vt+δ−Vt)+∣Ft]=s φ(0)=σVδ2π,\begin{aligned} &\mathbb{E}\bigl[(V_{t+\delta} - V_t)^{+} \mid \mathcal{F}_t\bigr] \\[0.4em] &\quad = s\, \varphi(0) = \frac{\sigma_V \sqrt{\delta}}{\sqrt{2\pi}}, \end{aligned}

so the expected gap exposure with Ct=VtC_t = V_t grows like the square root of the period, not linearly. The normal law is only a local diffusion approximation. Jumps, market moves linked to the default and large cash flows inside the period change the result. Initial margin that is usable at closeout enters the usable balance and lowers the gap exposure, the risk it is meant to cover.

In plain words After the last successful call the collateral stops moving, but the trades keep moving until they are closed out. The longer that gap and the more volatile the portfolio, the more value can build up that no collateral covers.

Example Continue the margin sequence. The counterparty defaults after the second margin date, the balance stays at 44 million, and the closeout value is 10.510.5 million, so the gap exposure is 10.5−4=6.510.5 - 4 = 6.5 million. It splits into 33 million left by the threshold, 0.40.4 million left by the minimum transfer rule and 3.13.1 million from the move during the margin period of risk. These are constructed states that show the order of events, not a forecast. With a constructed σV=4\sigma_V = 4 million per square root of a year and δ=0.04\delta = 0.04 years, about ten business days at 250250 per year, the move has standard deviation s=0.8s = 0.8 million, and with Ct=VtC_t = V_t the expected gap exposure is 0.8 φ(0)≈0.3190.8\, \varphi(0) \approx 0.319 million. Doubling δ\delta multiplies it by 2\sqrt{2}, to about 0.4510.451 million.

Check yourself

  1. Three trades with one counterparty have values 55, −3-3 and −4-4 million currency units from our side. Find our exposure with all three in one netting set and with no netting, and the counterparty’s exposure to us in both cases.
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The signed sum is 5−3−4=−25 - 3 - 4 = -2 million, so with netting our exposure is (−2)+=0(-2)^{+} = 0. The value −2-2 million is an obligation of ours, not an exposure of 22 million. Without netting our exposure is 5+0+0=55 + 0 + 0 = 5 million. From the counterparty’s side the values are −5-5, 33 and 44 million, so its netted exposure to us is 2+=22^{+} = 2 million and its exposure without netting is 0+3+4=70 + 3 + 4 = 7 million. Netting lowers the exposures of both sides, as the netting inequality predicts for the values and for their negatives.

  1. A one-sided margin rule has threshold H=3H = 3 million and minimum transfer amount M=1M = 1 million, and we hold 44 million of collateral. The marks at three successive margin dates are 55, 4.54.5 and 1.21.2 million. Find the balance and the exposure after each date. Then suppose the counterparty defaults after the third call but before the return settles, so that the balance is still the previous one and the closeout value is 1.21.2 million. What are the exposure and the net position in that case?
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At the first date the target is (5−3)+=2(5 - 3)^{+} = 2 million and the request is 2−4=−22 - 4 = -2 million. Its size is at least MM, so we return 22 million, the balance is 22 million and the exposure is 5−2=35 - 2 = 3 million. At the second date the target is 1.51.5 million and the request is −0.5-0.5 million, below MM in size, so nothing moves, the balance stays at 22 million and the exposure is 2.52.5 million, less than the threshold because the skipped return works in our favor. At the third date the target is 00 and the request is −2-2 million, so a return of 22 million is due, after which the balance is 00 and the exposure 1.21.2 million. If the default comes before that return settles, the balance is still 22 million, V−C=1.2−2=−0.8V - C = 1.2 - 2 = -0.8 million, the exposure is 00, and we owe 0.80.8 million to the counterparty on net. The minimum transfer test uses the size of the request, so it applies to returns as well as to new postings.

  1. In a constructed Gaussian approximation, the value change over the margin period of risk is normal with mean 00 and standard deviation s=0.8s = 0.8 million. At the last effective call the counterparty posted up to a threshold of H=0.5H = 0.5 million, so Ct=Vt−0.5C_t = V_t - 0.5 with Vt>0.5V_t > 0.5. Find the expected gap exposure and the probability that it exceeds 11 million, compare with H=0H = 0, and say why the numbers are only approximations.
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Write X=Vt+δ−VtX = V_{t+\delta} - V_t, so the gap exposure is (H+X)+(H + X)^{+}. Splitting the expectation at X=−HX = -H gives

E[(H+X)+]=H Φ(Hs)+s φ(Hs).\begin{aligned} &\mathbb{E}\bigl[(H + X)^{+}\bigr] \\[0.4em] &= H\, \Phi\bigl(\tfrac{H}{s}\bigr) + s\, \varphi\bigl(\tfrac{H}{s}\bigr). \end{aligned}

With H/s=0.625H/s = 0.625, the values Φ(0.625)≈0.7340\Phi(0.625) \approx 0.7340 and φ(0.625)≈0.3282\varphi(0.625) \approx 0.3282 give 0.5⋅0.7340+0.8⋅0.3282≈0.6300.5 \cdot 0.7340 + 0.8 \cdot 0.3282 \approx 0.630 million. The exposure exceeds 11 million when X>0.5X > 0.5, with probability 1−Φ(0.625)≈0.2661 - \Phi(0.625) \approx 0.266. With H=0H = 0 the expected gap exposure is 0.8 φ(0)≈0.3190.8\, \varphi(0) \approx 0.319 million and the probability is 1−Φ(1.25)≈0.1061 - \Phi(1.25) \approx 0.106. The threshold raises the expected gap exposure by about 0.3100.310 million, less than HH, because a downward move now uses up part of the residual that the threshold left. The normal law with zero mean is a local diffusion approximation, which leaves out jumps, market moves linked to the default and cash flows inside the period, and a minimum transfer amount can leave further value uncovered.

How this lesson connects