Unit 10, lesson 75

Credit default swap valuation

How a credit default swap is valued from its premium leg, including accrual on default, and its protection leg, how the par spread balances the two, and when it equals intensity times loss given default.

  • Video 75
  • Default models and credit default swaps

A protection buyer pays a running spread on a notional while a reference issuer survives, and receives the loss on the notional if the issuer defaults before maturity. Which spread makes these two promises equal in value when the contract starts? This lesson writes both payment streams as integrals against the default density, including the premium accrued between the last payment date and default, solves the par spread equation, and shows when the familiar product of intensity and loss given default is exact.

Key terms

Credit default swap

Definition A credit default swap on a reference issuer with default time τ\tau has a notional NN, a maturity TT, an annual spread ss and premium dates 0=t0<t1<⋯<tn=T0 = t_0 < t_1 < \dots < t_n = T with accrual fractions αi=ti−ti−1\alpha_i = t_i - t_{i-1}. In the simplified contract of this lesson the payments are the following.

  1. The protection buyer pays the premium sNαisN\alpha_i at tit_i if τ>ti\tau > t_i.
  2. If ti−1<τ≤tit_{i-1} < \tau \le t_i, the buyer pays the accrued premium sN(τ−ti−1)sN(\tau - t_{i-1}) at τ\tau, and no later premium is due.
  3. The protection seller pays N(1−R)N(1 - R) at τ\tau if τ≤T\tau \le T, where R∈[0,1]R \in [0, 1] is a fixed recovery rate.

The contract is valued under a pricing measure Q\mathbb{Q} with a deterministic discount factor D(t)=D(0,t)D(t) = D(0, t) and a survival function SS with a nonnegative piecewise continuous hazard rate λ\lambda, so that τ\tau has the density λS\lambda S on [0,T][0, T]. Neither the buyer nor the seller can default. Accrual fractions equal elapsed time here, and real contracts use their own day counts, calendars and settlement rules, which enter the same cash-flow calculation. The value of the swap to the protection buyer is the value of the protection leg minus the value of the premium leg, and its value to the seller is the negative of that.

In plain words A credit default swap is protection on a notional against an issuer’s default, bought with a running premium. The buyer pays while the issuer is alive, the seller pays the loss once if default comes first, and both payment streams stop at default.

Example The constructed contract of this lesson has N=1N = 1, T=3T = 3 years and quarterly dates tj=j/4t_j = j/4 for j=1,…,12j = 1, \dots, 12, with r=0.02r = 0.02, λ=0.05\lambda = 0.05 per year and R=0.40R = 0.40, all constant under Q\mathbb{Q}. Suppose default happens at τ=1.1\tau = 1.1. The buyer has paid four quarterly premiums of s/4s/4, pays the accrued premium 0.1 s0.1\,s at τ\tau and receives 0.60.6, and then the swap ends.

Premium leg

Definition Under the assumptions of the previous card, the premium leg is worth Vprem=sNAV^{\text{prem}} = sNA, where the risky annuity A=Asch+AaccA = A^{\text{sch}} + A^{\text{acc}} has a scheduled part and an accrual part,

Asch=∑i=1nαiD(ti)S(ti),Aacc=∑i=1nai.\begin{aligned} A^{\text{sch}} &= \sum_{i=1}^{n} \alpha_i D(t_i) S(t_i), \\[0.4em] A^{\text{acc}} &= \sum_{i=1}^{n} a_i . \end{aligned}

The scheduled premium at tit_i is paid only on the event {τ>ti}\{\tau > t_i\}, which has probability S(ti)S(t_i), and the accrual terms aia_i of the next card value the premium owed at default. The annuity is measured in years, discounted and weighted by survival, so sNAsNA is in currency units. The premium leg is the payment stream of the protection buyer.

In plain words The risky annuity is the value of receiving one unit of spread per year, on the contract’s schedule, for as long as the issuer survives. A premium counts only in the states where the issuer is still alive on its payment date.

Example In the constructed contract D(t)S(t)=e−0.07tD(t)S(t) = e^{-0.07t}, so the scheduled part is a geometric sum,

Asch=14∑j=112e−0.0175j≈2.682331\begin{aligned} A^{\text{sch}} &= \tfrac14 \sum_{j=1}^{12} e^{-0.0175 j} \\[0.4em] &\approx 2.682331 \end{aligned}

years. Adding the accrual part 0.0168630.016863 of the next card gives A≈2.699194A \approx 2.699194 years. At a spread of 300300 bp on a notional of 10 million, the premium leg is worth about 0.03⋅2.699194⋅107≈8097580.03 \cdot 2.699194 \cdot 10^{7} \approx 809758 currency units.

Accrual on default

Definition Accrual on default is the premium for the part of the current period that has elapsed at default, the amount sN(τ−ti−1)sN(\tau - t_{i-1}) paid at τ\tau when ti−1<τ≤tit_{i-1} < \tau \le t_i. Its contribution to the annuity from period ii is

ai=∫ti−1ti(t−ti−1)×D(t) λ(t)S(t) dt.\begin{aligned} a_i &= \int_{t_{i-1}}^{t_i} (t - t_{i-1}) \\[0.4em] &\qquad \times D(t)\, \lambda(t) S(t)\,dt . \end{aligned}

For a constant rate rr, a constant intensity λ\lambda and periods of equal length δ\delta, write k=r+λk = r + \lambda. The substitution t=ti−1+ut = t_{i-1} + u gives ai=λe−kti−1∫0δu e−ku dua_i = \lambda e^{-k t_{i-1}} \int_0^{\delta} u\, e^{-ku}\,du, and integration by parts, differentiating uu and integrating e−kue^{-ku}, gives for k≠0k \ne 0

∫0δu e−ku du=1−e−kδ(1+kδ)k2,\begin{aligned} &\int_0^{\delta} u\, e^{-ku}\,du \\[0.4em] &\quad = \frac{1 - e^{-k\delta}(1 + k\delta)}{k^2}, \end{aligned}

with the limit δ2/2\delta^2/2 as k→0k \to 0. For small kδk\delta the integral is 12δ2(1−23kδ+O(k2δ2))\tfrac12\delta^2\bigl(1 - \tfrac23 k\delta + O(k^2\delta^2)\bigr), so each aia_i is close to 12δ⋅λδ e−kti−1\tfrac12\delta \cdot \lambda\delta\, e^{-k t_{i-1}}. That is half a period of premium times the approximate default probability λδ S(ti−1)\lambda\delta\, S(t_{i-1}) of the period, discounted by D(ti−1)D(t_{i-1}), which is where the common half-period approximation of the accrual comes from.

In plain words A default early in a period owes little accrued premium, and a default near its end owes almost a full period. The factor t−ti−1t - t_{i-1} inside the integral keeps track of where in the period the default falls.

Example For the constructed contract kδ=0.07⋅0.25=0.0175k\delta = 0.07 \cdot 0.25 = 0.0175, and the integral is about 0.0308880.030888, close to δ2/2=0.03125\delta^2/2 = 0.03125. The first period contributes 0.05⋅0.030888≈0.0015440.05 \cdot 0.030888 \approx 0.001544, and the twelve periods together give

Aacc=0.05⋅0.030888×∑j=011e−0.0175j≈0.016863\begin{aligned} A^{\text{acc}} &= 0.05 \cdot 0.030888 \\[0.4em] &\quad \times \sum_{j=0}^{11} e^{-0.0175 j} \\[0.4em] &\approx 0.016863 \end{aligned}

years. Leaving out the accrual makes the par spread 302.64302.64 bp instead of 300.75300.75 bp, because the protection leg is unchanged and a smaller annuity has to be balanced by a larger spread.

Protection leg

Definition Under the assumptions of the first card the protection leg is worth

Vprot=N(1−R)×∫0TD(t) λ(t)S(t) dt,\begin{aligned} V^{\text{prot}} &= N(1 - R) \\[0.4em] &\quad \times \int_0^T D(t)\, \lambda(t) S(t)\,dt , \end{aligned}

the loss on the notional discounted from each possible default date and weighted by the default density. For constant rr and λ\lambda with k=r+λ≠0k = r + \lambda \ne 0 it equals

Vprot=N(1−R)λ×1−e−kTk.\begin{aligned} V^{\text{prot}} &= N(1 - R)\lambda \\[0.4em] &\quad \times \frac{1 - e^{-kT}}{k} . \end{aligned}

The recovery rate enters only through the loss given default 1−R1 - R, so with the survival curve held fixed the protection value is proportional to 1−R1 - R. Payment at the default date is an idealization of the settlement process of real contracts.

In plain words The protection payment has one size but many possible dates. Its value adds up the discounted payment over every date at which default can happen, each weighted by how likely default is near that date.

Example For the constructed contract

Vprot=0.03 (1−e−0.21)0.07≈0.081178\begin{aligned} V^{\text{prot}} &= \frac{0.03\,\bigl(1 - e^{-0.21}\bigr)}{0.07} \\[0.4em] &\approx 0.081178 \end{aligned}

per unit notional. The factor 0.030.03 is the loss given default 0.60.6 times the intensity 0.050.05, and 0.21=kT0.21 = kT. Lowering the recovery rate to 0.250.25 with the same survival curve multiplies the protection value by 0.75/0.6=1.250.75/0.6 = 1.25, to about 0.1014730.101473, and leaves the annuity unchanged.

Par spread

Definition The par spread of a credit default swap is

spar=VprotNA,s_{\text{par}} = \frac{V^{\text{prot}}}{NA},

defined when A>0A > 0. For a contract with spread ss, the value to the protection buyer is then Vprot−sNA=NA (spar−s)V^{\text{prot}} - sNA = NA\,(s_{\text{par}} - s). A new contract struck at the par spread has zero initial value, and the notional cancels from spars_{\text{par}} because both legs are proportional to it. For an existing contract with s≠spars \ne s_{\text{par}} the two legs no longer cancel, and the buyer’s value is positive exactly when s<spars < s_{\text{par}}. For a contract that trades with a fixed coupon cc and an upfront payment UU from buyer to seller, the same balance in this model gives U=Vprot−cNA=NA (spar−c)U = V^{\text{prot}} - cNA = NA\,(s_{\text{par}} - c), and real upfront quotes need further contractual inputs. When a survival curve is fitted to a set of quotes, piecewise constant nonnegative intensities keep SS positive and nonincreasing through the exponential formula. A fit that needs a negative intensity signals inconsistent quotes, discounting, recovery assumption or fitting constraints, and it cannot be read as a conditional default rate.

In plain words The par spread is the running premium at which the buyer’s discounted expected payments equal the seller’s. The protection value comes first, the annuity second, and only then are they divided.

Example For the constructed contract

spar=0.0811782.699194≈0.030075,\begin{aligned} s_{\text{par}} &= \frac{0.081178}{2.699194} \\[0.4em] &\approx 0.030075 , \end{aligned}

about 300.75300.75 bp per year. A buyer who holds a contract at 250250 bp has the value 2.699194⋅(0.030075−0.025)≈0.0136982.699194 \cdot (0.030075 - 0.025) \approx 0.013698 per unit notional, about 136983136983 currency units on a notional of 10 million, and the seller has the negative of that. With recovery 0.250.25 and the same survival curve the par spread is about 375.94375.94 bp. If instead the quote of 300.75300.75 bp is held fixed while the recovery assumption changes to 0.250.25, refitting a constant intensity gives about 0.04000.0400 instead of 0.050.05, so the fitted survival curve depends on the recovery assumption.

Continuous premium benchmark

Definition If the premium were paid continuously at the rate sNsN per year while the issuer survives, up to TT, the annuity would be ∫0TD(t)S(t) dt\int_0^T D(t) S(t)\,dt and the par spread would be

scont=(1−R) ∫0TDλS dt∫0TDS dt,s_{\text{cont}} = (1 - R)\, \frac{\int_0^T D \lambda S\,dt}{\int_0^T D S\,dt} ,

the loss given default times a weighted average of the intensity. For a constant intensity it equals (1−R)λ(1 - R)\lambda exactly, for every deterministic discount curve. With scheduled payments and exact accrual, the buyer pays in each period sNsN times exactly the time the issuer was alive in that period, the same amount as with continuous payment, but at the period end or at default instead of along the way. So if D≡1D \equiv 1 the annuity equals the continuous one and spar=sconts_{\text{par}} = s_{\text{cont}}, and if DD is strictly decreasing, as with positive rates, the annuity is smaller and spar>sconts_{\text{par}} > s_{\text{cont}}. As the periods shrink with TT fixed, the scheduled sum converges to the continuous annuity and the accrual part to zero, so spar→sconts_{\text{par}} \to s_{\text{cont}}. For scheduled premiums the relation spar≈(1−R)λs_{\text{par}} \approx (1 - R)\lambda is therefore an approximation.

In plain words With continuous premiums both legs contain the same survival-weighted discount integral, and it cancels from the ratio. Scheduled premiums pay the same amounts a little later, and that delay alone moves the par spread away from the product of intensity and loss given default.

Example For the constructed curve the continuous annuity is (1−e−0.21)/0.07≈2.705939(1 - e^{-0.21})/0.07 \approx 2.705939 years, and 0.081178/2.705939≈0.030.081178/2.705939 \approx 0.03, which is 300300 bp and exact before rounding. The quarterly contract with accrual needs about 300.75300.75 bp, a monthly schedule about 300.25300.25 bp and a semiannual one about 301.50301.50 bp. With zero rates the quarterly contract with accrual gives exactly 300300 bp, while without accrual it gives about 301.88301.88 bp, because the premium for the partial period before default is then never paid. Inverting the benchmark on the quarterly par spread gives 0.030075/0.6≈0.0501250.030075/0.6 \approx 0.050125, slightly above the true intensity 0.050.05.

Check yourself

  1. In the continuous premium benchmark with a constant intensity, find the par spread for λ=0.02\lambda = 0.02 per year and R=0.40R = 0.40. Which intensity does a par spread of 180180 bp imply with R=0.40R = 0.40, and which with R=0.25R = 0.25?
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The benchmark gives scont=(1−R)λ=0.6⋅0.02=0.012s_{\text{cont}} = (1 - R)\lambda = 0.6 \cdot 0.02 = 0.012, which is 120120 bp. A spread of 180180 bp implies λ=0.018/0.6=0.03\lambda = 0.018/0.6 = 0.03 per year with R=0.40R = 0.40 and λ=0.018/0.75=0.024\lambda = 0.018/0.75 = 0.024 per year with R=0.25R = 0.25, so the implied intensity depends on the recovery assumption. The intensity 0.030.03 is a rate, and the one-year risk-neutral default probability it implies is 1−e−0.03≈0.0295541 - e^{-0.03} \approx 0.029554. For a contract with scheduled premiums these intensities are approximations, slightly too high when rates are positive.

  1. A one-year contract has a single premium date at t1=1t_1 = 1, with r=0.03r = 0.03, λ=0.05\lambda = 0.05 per year and R=0.40R = 0.40, all constant. Find the risky annuity with and without accrual on default, the protection value per unit notional and both par spreads, and compare them with 300300 bp.
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Here k=0.08k = 0.08 and δ=1\delta = 1. The scheduled part is Asch=e−0.08≈0.923116A^{\text{sch}} = e^{-0.08} \approx 0.923116. The accrual integral is

1−1.08 e−0.080.0064≈0.0030340.0064≈0.474117,\begin{aligned} \frac{1 - 1.08\, e^{-0.08}}{0.0064} &\approx \frac{0.003034}{0.0064} \\[0.4em] &\approx 0.474117 , \end{aligned}

so Aacc≈0.05⋅0.474117≈0.023706A^{\text{acc}} \approx 0.05 \cdot 0.474117 \approx 0.023706 and A≈0.946822A \approx 0.946822. The protection value is 0.6⋅0.05 (1−e−0.08)/0.08≈0.0288310.6 \cdot 0.05\,(1 - e^{-0.08})/0.08 \approx 0.028831. The par spread is 0.028831/0.946822≈0.0304510.028831/0.946822 \approx 0.030451, about 304.51304.51 bp, and without accrual it is 0.028831/0.923116≈0.0312330.028831/0.923116 \approx 0.031233, about 312.33312.33 bp. Both exceed the benchmark 300300 bp. With the same inputs and quarterly dates they would be about 301.13301.13 bp and 303.02303.02 bp. The annual schedule delays the premiums more, and leaving out the accrual matters more because a default can then forgive up to a full year of premium.

  1. A fund bought protection on a notional of 10 million at 350350 bp. The current curve is the constructed one, with risky annuity 2.6991942.699194 and par spread about 300.75300.75 bp. What is the contract worth to the fund and to the protection seller, and how does the answer change if the contract spread is 250250 bp?
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The value to the protection buyer is the protection leg minus the premium leg,

NA (spar−s)≈107⋅2.699194×(0.030075−0.035),\begin{aligned} &NA\,(s_{\text{par}} - s) \\[0.4em] &\approx 10^{7} \cdot 2.699194 \\[0.4em] &\quad \times (0.030075 - 0.035) , \end{aligned}

which is about −132936-132936 currency units. The fund pays more than the current par spread for the same protection, so the contract is a liability for it, and the seller holds an asset worth about 132936132936. The protection leg does not depend on the contract spread, so only the premium leg changes when ss does. At 250250 bp the sign flips, the fund’s value is about +136983+136983 and the seller’s about −136983-136983. Writing the buyer’s value as premium leg minus protection leg would reverse every sign.

How this lesson connects