A can of soup, a drill bit, a water tower. Many solids are round about a vertical axis, and describing them with and leads to square roots everywhere. Cylindrical coordinates keep the height and use polar coordinates in the horizontal plane, so the round parts become simple bounds on and .
Key terms
Cylindrical coordinates
Definition A point in a right-handed coordinate system has cylindrical coordinates , where are polar coordinates of the projection and is unchanged.
We take , so is the distance from to the -axis, and is measured counterclockwise from the positive -axis when viewed from above. The angle is determined only up to multiples of , and not at all on the -axis. The coordinate surfaces are the cylinder for , the half-plane bounded by the -axis, and the horizontal plane .
In plain words Drop the point straight down to the -plane, describe the shadow in polar coordinates, and keep the height.
Example The point has , with the shadow in the first quadrant, so , and . It sits where the cylinder , the half-plane and the plane meet.
The volume element r dr dθ dz
Definition The small solid with , and , with and , is a cylindrical wedge. Its base is a piece of an annulus with area , so its volume is exactly
Riemann sums over such wedges lead to the volume element . The same factor is the Jacobian, since the change of variables has determinant .
In plain words A step in angle covers an arc of length , which is longer far from the axis. That is where the extra comes from. Forgetting it is the most common mistake in this topic.
Example The wedge , , is a quarter of a thick pipe. Its exact volume is
and the formula gives the same, .
Cylindrical regions
Definition Let be a solid of type 1 whose projection onto the -plane is described in polar coordinates by
with and , continuous with . Let lie between the graphs and , with continuous on . If is continuous on , then
where and is evaluated at .
In plain words Find the shadow, describe it in polar form, write the bottom and top surfaces in terms of and , and remember the .
Example The solid inside the cylinder , above and below the paraboloid has shadow the disk , and the top is , which stays positive on that disk. So
Bounds from surfaces and projections
Definition To find the bounds of a solid in cylindrical coordinates, write each bounding surface in terms of , and , using . Decide which surface is the bottom and which is the top for each point of the shadow. The shadow’s outer edge is usually where the bottom and top surfaces meet, found by setting their values equal.
In plain words The curve where the lid meets the floor marks the edge of the shadow. Inside it, check one point to see which surface is on top.
Example Take the solid above the cone and below the paraboloid . In cylindrical form these are and . They meet where , so and . At the paraboloid is higher, so it is the top. The volume is
Integration order
Definition For continuous on the solid, Fubini’s theorem, applied to the integrand over the region the solid occupies in space, lets the integration in , and be done in any order, provided the bounds of each inner variable are rebuilt from the inequalities that describe the solid. When the outer variable is , the slice at height is a horizontal region, and if the surface bounding that slice changes at some height, the integral must be split there.
In plain words Slicing by height instead of by radius is a different way of reading the same solid. It is also a good independent check of an answer.
Example Slice the cone and paraboloid solid above by height. For the slice is the disk , cut by the cone. For it is the disk , cut by the paraboloid. So
the same as before.
Symmetry
Definition Suppose is continuous on a solid . If is unchanged by the reflection and on , then . The same holds with the roles of and exchanged, for the reflection and odd in . If is unchanged by every rotation about the -axis, so that its bounds do not involve and runs over a full turn, and depends only on and , then the integral gives a factor . For such a solid with a density that depends only on and , the center of mass lies on the -axis.
In plain words Before integrating, look for halves that cancel and for a full turn that contributes just .
Example The cone and paraboloid solid with constant density is symmetric about the -axis, so with no computation. For the height,
so dividing by gives . The centroid is .
Mass and moment of inertia
Definition For a solid with continuous density , the mass and the moment of inertia about the -axis are
because is the squared distance to the -axis.
In plain words The moment of inertia measures how hard the solid is to spin about the axis. Mass far from the axis counts more, by the square of its distance.
Example A cylinder of radius and height has density , so it is denser near the rim. Then
The ratio is , larger than the value for a uniform cylinder, because more of the mass sits near the rim.
Check yourself
- Find cylindrical coordinates of the point .
Show the answer
The distance to the axis is . The shadow lies in the second quadrant with , so . The point is .
- Evaluate the integral of over the solid cylinder , .
Show the answer
The cylinder is symmetric under and is odd, so the part is . For the part, every horizontal slice has area , so the integral is .
- Find the mass of the solid between the paraboloid and the plane with density , and check it by slicing.
Show the answer
The surfaces meet at , and the plane is on top. So
As a check, the slice at height is a disk of radius and area , so the mass is .