Why arccosine reverses the decreasing cosine branch over the upper half of the unit circle, how to find its exact values, and how its domain, range, endpoints and graph follow from that choice.
The angle between two directions is never negative and never more than a half turn. If you know its cosine, you want back exactly one angle between 0 and π. Arccosine does that job. Its interval differs from the one arcsine uses, and there is a good reason for that.
Key terms
Restricted cosine branch
Definition The restricted cosine branch is the cosine function with its domain cut down to the closed interval [0,π]. On this interval cosine decreases from cos0=1 to cosπ=−1 and takes every value in [−1,1] exactly once, so it is one-to-one with range [−1,1]. The interval [−2π,2π] used for sine would not work, since cosine is even and cos(−3π)=cos3π.
In plain words On the unit circle, angles from 0 to π sweep the upper half. Each x-coordinate between −1 and 1 belongs to exactly one point of that upper arc, so the angle is determined by its cosine.
Example The equation cosx=0 has the solutions 2π+kπ for every integer k. Of these, only 2π lies in [0,π].
Arccosine
Definition For −1≤u≤1, the arccosine of u is the unique angle θ in radians with
0≤θ≤πandcosθ=u.
It is written θ=arccosu or θ=cos−1u, where cos−1 means the inverse function and not the reciprocal cosu1=secu. The inverse identities are
cos(arccosu)=u for every u∈[−1,1],arccos(cosθ)=θ only for θ∈[0,π].
In plain words The expression arccosu asks which angle between 0 and π has cosine u. There is exactly one.
Example The angle 3π has cosine 21. A cosine of −21 needs a point on the left side of the upper arc with the same reference angle, so
arccos(−21)=π−3π=32π.
Principal angle
Definition The value arccosu is the principal angle with cosine u. It always lies in [0,π], so it is never negative. It is acute when u>0, a right angle when u=0 and obtuse when u<0. For negative inputs the identity
arccos(−u)=π−arccosu,−1≤u≤1,
holds, because cos(π−θ)=−cosθ and π−θ stays in [0,π] when θ does. Every other angle with cosine u is ±arccosu+2kπ for some integer k.
In plain words A negative input does not give a negative angle. It gives an obtuse angle, on the left half of the upper arc.
Example Since arccos22=4π, the identity gives
arccos(−22)=π−4π=43π.
The answer −4π would be wrong twice over, since it is negative and its cosine is +22.
Decreasing function
Definition Arccosine is decreasing on [−1,1], which means that −1≤u1<u2≤1 implies arccosu1>arccosu2. It inherits this from the restricted cosine branch, which is decreasing. Arccosine is neither even nor odd. Its graph is instead symmetric about the point (0,2π), which is what the identity arccos(−u)=π−arccosu says.
In plain words The larger the cosine, the smaller the angle. An input of 1 gives the smallest angle and an input of −1 gives the largest.
Example Three inputs in increasing order give angles in decreasing order.
arccos(−21)=32π>arccos0=2π>arccos21=3π.
The values at −21 and 21 are neither equal nor opposite, so arccosine is not even and not odd.
Domain
Definition The domain of arccosine is the closed interval [−1,1]. For a composition arccos(g(x)) the domain is the set of x in the domain of g with −1≤g(x)≤1.
In plain words Arccosine accepts exactly the numbers that can be cosines.
Example The expression arccos(−1.2) is undefined. For h(x)=arccos(x−2) the condition −1≤x−2≤1 gives the domain [1,3].
Range
Definition The range of arccosine is the closed interval [0,π], the domain of the restricted cosine branch. Every value in it is attained.
In plain words Arccosine always answers with an angle from 0 to a half turn.
Example Because cos(−3π)=21, we get arccos(cos(−3π))=3π and not −3π. The same happens at 35π, since cos35π=21 as well. The output has to land in [0,π], whatever angle went in.
Endpoint values
Definition The landmark values of arccosine are
arccos(−1)=π,arccos0=2π,arccos1=0.
The first and last are attained at the included endpoints of the domain, and 2π is an interior value. So the graph begins at the solid point (−1,π) and ends at the solid point (1,0).
In plain words The ends of the curve are real points of the function. An input of 1 gives angle 0 and an input of −1 gives a straight angle.
Example For h(x)=arccos(x−2) on [1,3] the landmarks are h(1)=π, h(2)=2π and h(3)=0, so its range is still [0,π].
Inverse graph
Definition The graph of y=arccosx is the set of points (b,a) for which (a,b) lies on the graph of y=cosx with 0≤x≤π. Swapping the coordinates is what is meant by reflecting across the line y=x, and the picture looks like a mirror image only when both axes use the same scale. The curve falls from (−1,π) through (0,2π) to (1,0). The cosine branch has horizontal tangent lines at θ=0 and θ=π, so the arccosine graph has vertical tangent lines at its endpoints (−1,π) and (1,0) and falls more and more steeply as x approaches −1 or 1.
In plain words Take the falling arch of cosine between 0 and π, swap x and y in every point, and the arccosine curve appears, still falling.
Example For the scaled input y=arccos2x the domain is [−2,2], twice as wide. The arccosine graph is stretched horizontally by a factor of 2, so each point (a,b) moves to (2a,b).
x
−2
−1
0
1
2
arccos2x
π
32π
2π
3π
0
The range is [0,π], with solid dots at (−2,π) and (2,0).
Check yourself
Find the exact value of arccos(−23).
Show the answer
Since arccos23=6π, the identity for negative inputs gives
arccos(−23)=π−6π=65π.
Find the domain, the range and the endpoints of the graph of y=arccos2x.
Show the answer
The condition −1≤2x≤1 gives the domain [−21,21]. The graph starts at the solid point (−21,π), passes through (0,2π) and ends at the solid point (21,0). The range is [0,π].
Find arccos(cos34π).
Show the answer
The inner value is cos34π=−21, and the angle in [0,π] with that cosine is 32π. The answer is 32π, because 34π lies outside [0,π].
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