Push a child on a swing once per swing and the arcs keep growing. Push at a slightly different rhythm and the motion can swell and fade by turns, and with enough friction it settles into a steady size. Which of these happens depends on how the driving frequency compares with the natural frequency, and on the damping. This lesson adds a periodic force to the mass-spring model and separates three behaviors, beats from two nearby frequencies, the linear growth of undamped resonance and the finite amplitude peak that damping allows.
Key terms
Forced oscillation
Definition Let be time and let primes denote derivatives with respect to . A forced oscillation is a solution of
where , and are the mass, stiffness and damping coefficient of the free model, is the force amplitude in newtons and is the driving angular frequency in radians per second, so the force completes cycles per second. Every solution has the form , where is any one particular solution and is a free solution of the homogeneous equation, chosen to match the initial data. Without damping, and with , one particular solution is
In plain words The drive keeps pushing at its own rhythm. The response is one motion that follows the drive plus whatever free motion the starting conditions leave behind.
Example For the trial gives , so and every solution is . Driving the same system faster, with , gives . Below the natural frequency the forced motion moves with the force, and above it the forced motion moves against the force.
Natural angular frequency
Definition The natural angular frequency of the oscillator is
measured in radians per second. It is the angular frequency of free undamped motion , whose period is and whose ordinary frequency is cycles per second. It depends only on and . It is different from the driving angular frequency , which is set from outside, and from the damped angular frequency of an underdamped system, which is smaller.
In plain words A mass on a spring has its own rhythm, the one it swings at when left alone without friction. Every drive is measured against that rhythm.
Example For and the natural angular frequency is radians per second. One free cycle takes seconds, about cycles per second. Doubling the mass lowers it to radians per second.
Beats
Definition Beats are the slow periodic swelling and fading of an oscillation that is the sum of two oscillations with nearby frequencies. In an undamped forced oscillator (, ) started from rest, and , the response is with . The difference of cosines identity turns it into a product,
When is close to , the second factor oscillates fast and the first changes slowly, so the slow factor sets the size of the fast oscillation. The magnitude envelope repeats with the beat period
while the signed slow factor takes twice as long to repeat. For every fixed the response stays bounded, with .
In plain words The drive and the free motion drift in and out of step. In step their effects add, out of step they cancel, so the size of the motion rises and falls slowly.
Example Take , and , so , and drive with from rest. The particular solution starts at , so subtract the free solution . Both cosines have zero velocity at , so the velocity condition holds too, and
The envelope has period , and the motion reaches its largest size at , where . The frequencies and are not very close, so each beat holds only a few fast oscillations. Closer frequencies give slower beats with more oscillations inside each one.
Undamped resonance
Definition Undamped resonance is the case and . The usual trial solves the homogeneous equation, so substituting it gives and never the force. Multiplying the trial by , as the modification rule of undetermined coefficients prescribes, gives the particular solution
It also satisfies and , so it is the response from rest. Every other solution adds a bounded free oscillation to it, so every solution is unbounded as .
In plain words Each push arrives at the same point of every swing, so the pushes keep adding up instead of canceling, and without damping nothing removes the energy they supply.
Example Keep , and , and drive with . The trial fails, since . For ,
so . Also and , so is the response from rest. It matches the formula, since .
Secular growth
Definition Secular growth is growth of an oscillation’s envelope in proportion to a power of , here to itself. For the resonant response from rest satisfies
with equality whenever , so its envelope is a pair of straight lines through the origin with slopes . Unlike beats, which stay below a fixed bound, secular growth passes every bound. A real spring eventually leaves its linear range, and any damping keeps the amplitude bounded.
In plain words The swings grow by about the same amount every cycle, without limit.
Example Resonance is the limit of beats. For fixed , L’Hôpital’s rule in the variable gives
as , so the beat response from rest approaches the resonant one while the beat period grows without bound. For the envelope is the pair of lines , and near the swings reach a size of about .
Damped amplitude peak
Definition Let , and be positive. Undetermined coefficients give exactly one particular solution of the form , and its amplitude is
where . Since , the two squares never vanish together, so is finite at every driving frequency. With , a number that may be negative, differentiating gives
So the amplitude has a maximum at a positive frequency if and only if , and the peak is then at
with largest amplitude . If , the amplitude decreases for all and stays below its zero-frequency value , the static deflection. The condition is stronger than underdamping, which asks only , and a peak, when it exists, lies below both frequencies, . Some books call this peak practical resonance.
In plain words Damping caps the response, so the amplitude curve has a finite hump instead of a spike. The hump appears only when the damping is light enough, and its top sits a little below the natural frequency.
Example Take , , and . Here , so the peak is at radians per second, below . With the largest amplitude is . For comparison, and . Because , every free part decays, so this periodic solution is the long-run motion, the sinusoidal steady state.
Check yourself
- A body of mass on a spring with has no damping. Find its natural angular frequency, and the beat period when it is driven from rest at radians per second.
Show the answer
The natural angular frequency is radians per second. The beat period is
seconds. That is the time between successive maxima of the magnitude envelope. The signed slow factor takes seconds to repeat, and the fast factor oscillates at radians per second.
- Solve with and , where primes are derivatives in . Why does the trial fail?
Show the answer
The natural angular frequency is , the same as the driving frequency. Every function satisfies , so it can never produce . Try instead. Then , so , and
Matching gives and , so . This function has and , so and it is the response from rest. Its envelope is , which is secular growth.
- A system with , and is underdamped. Does its amplitude curve have a peak at a positive driving frequency?
Show the answer
It is underdamped because . But , so there is no peak at a positive frequency. Directly,
for , so increases and decreases. The amplitude stays below its zero-frequency value , the static deflection. Underdamping decides whether free motion oscillates, while a positive-frequency peak needs the stronger condition .